The area of the arrow given in the figure is 610 square cm
<h3>Area of composite figure</h3>
The given figure is made up of rectangle and triangle. The area is expressed as:
Area = Area of rectangle + area of triangle
Substitute the given parameters
Area of the arrow = (15*20) + 0.5(31 * 20)
Area of the arrow = 300 + 310
Area of the arrow = 610 square cm
Hence the area of the arrow given in the figure is 610 square cm
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Answer:
3.56m
Step-by-step explanation:Parameters given:
Area of the rectangular garden = 16.02m^2
Length of the rectangular garden = 4.5m
The Area of a rectangle can be calculated for using the formula below
Area (square meters) = length (meters) × width (meters)
Therefore, 16.02m^2 = 4.5m × width
Width = 16.02m^2 / 4.5m
Width = 3.56m
Therefore the width in meters of the garden is 3.56m
See the attachment below for an illustrative diagram
A = area
l = length
w = width
If that 40% is how many are occupied then- 100 are occupied 150 are vacant
if that 40% is how many are vacant then- 100 are vacant and 150 are occupied
Answer:
A) w=3
Step-by-step explanation:
4 x 3 = 12
This is the work when you plug in the numbers in the varible w
Since h represents the height of the ball at any given time, t, let h = 25, such that the ball will be 25m high at t.
Now, we have 25 = 20t - 5t²
5t² - 20t + 25 = 0
t² - 4t + 5 = 0
Since the discriminant is less than zero, there are no solutions.
Hence, the ball will never be 25m high.
