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lubasha [3.4K]
3 years ago
5

Perform the indicated operation. x/x + 1 - 1/x - 1 + 2x/x^2 - 1 =

Mathematics
1 answer:
luda_lava [24]3 years ago
4 0
\frac{x}{x + 1} - \frac{1}{x - 1} + \frac{2x}{x^{2} - 1}
\frac{x}{x + 1} - \frac{1}{x - 1} + \frac{2x}{(x + 1)(x - 1)}
\frac{x(x - 1)}{(x + 1)(x - 1)} - \frac{1(x + 1)}{(x + 1)(x - 1)} + \frac{2x}{(x + 1)(x - 1)}
\frac{x^{2} - x}{(x + 1)(x - 1)} - \frac{x + 1}{(x + 1)(x - 1)} + \frac{2x}{(x + 1)(x - 1)}
\frac{x^{2} - x + x + 1 + 2x}{(x + 1)(x - 1)}
\frac{x^{2} + 2x + 1}{(x + 1)(x - 1)}
\frac{(x + 1)(x + 1)}{(x + 1)(x - 1)}
\frac{(x + 1)^{2}}{(x + 1)(x - 1)}
\frac{x + 1}{x - 1}
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What is the median to 132, 183, 191, 237, 251, 277, 279, 334, 448, 599?<br>​
V125BC [204]

Answer:

264

Step-by-step explanation:

(251 + 277) / 2 = 264

3 0
3 years ago
you are running a fuel economy study. One of the cars you find is blue. It can travel 31 1/2 miles on 1 1/4 gallons of gasoline.
SIZIF [17.4K]

Answer:

Step-by-step explanation:

<u><em>Blue Car:</em></u>  (31 1/2 miles)/(1 1/4 gallons)

(63/2) miles / (5/4) gallons

(63/2)*(4/5) = <u>25.2 miles/gallon.</u>

<u><em>Red Car:</em></u>  (27 1/5 miles)/(4/5 gallon)

= <u>34 miles/gallon.</u>

The Red Car will travel the furthest.

7 0
2 years ago
Choose a method . Then find the product 10x15
34kurt

Answer:

150

Step-by-step explanation:

15*10

Lets get rid of the 0 for now

15*1

That is 15 added to itself 0 times so it is 15

Now lets put the 0 back

and we will get

150

5 0
3 years ago
Read 2 more answers
15x -5 = 45 + 19 what is x
SCORPION-xisa [38]

Answer:

x equals 4.6

Step-by-step explanation:

if u need explanation plz tell me so i can help

4 0
3 years ago
Read 2 more answers
1. Write a two-column proof.
Alexandra [31]

Answer:

Check it below, please

Step-by-step explanation:

Hi there!

Let's prove segment AB is perpendicular to CD. Attention to the fact that a two column proof has to be concise. So all the comments can't be exhaustive, but as short as possible.

Let's recap: An isosceles triangle is one triangle with at least 2 congruent angles.

Statement                     Reason

\overline{AB} \cong \overline{AC}\\                     Given

\widehat{ACB} \:bisects\: \overline{AB}        Isosceles Triangle the altitude, the bisector coincide.          

\overline{AD} \cong \overline{DB}               Bisector equally divide a line segment into two congruent      

m\angle CDA =m \angle CBD=90^{\circ} Right angles, perpendicular lines.                  

\overline{CD}\perp \overline{AB}                    Perpendicular Line segment      

8 0
3 years ago
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