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lubasha [3.4K]
3 years ago
5

Perform the indicated operation. x/x + 1 - 1/x - 1 + 2x/x^2 - 1 =

Mathematics
1 answer:
luda_lava [24]3 years ago
4 0
\frac{x}{x + 1} - \frac{1}{x - 1} + \frac{2x}{x^{2} - 1}
\frac{x}{x + 1} - \frac{1}{x - 1} + \frac{2x}{(x + 1)(x - 1)}
\frac{x(x - 1)}{(x + 1)(x - 1)} - \frac{1(x + 1)}{(x + 1)(x - 1)} + \frac{2x}{(x + 1)(x - 1)}
\frac{x^{2} - x}{(x + 1)(x - 1)} - \frac{x + 1}{(x + 1)(x - 1)} + \frac{2x}{(x + 1)(x - 1)}
\frac{x^{2} - x + x + 1 + 2x}{(x + 1)(x - 1)}
\frac{x^{2} + 2x + 1}{(x + 1)(x - 1)}
\frac{(x + 1)(x + 1)}{(x + 1)(x - 1)}
\frac{(x + 1)^{2}}{(x + 1)(x - 1)}
\frac{x + 1}{x - 1}
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vekshin1

Answer:

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