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sattari [20]
4 years ago
6

Help with my robotics hw

Computers and Technology
1 answer:
Tamiku [17]4 years ago
7 0

Answer: 1: 50

2:

Explanation:

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The program in Python is as follows:

BCD = ["0001","0010","0011","0100","0101","0110","0111"]

num = input("Decimal: ")

BCDValue = ""

valid = True

for i in range(len(num)):

   if num[i].isdigit():

       if(int(num[i])>= 0 and int(num[i])<8):

           BCDValue += BCD[i]+" "

       else:

           valid = False

           break;

   else:

       valid = False

       break;

if(valid):

   print(BCDValue)

else:

   print("Invalid")

Explanation:

This initializes the BCD corresponding value of the decimal number to a list

BCD = ["0001","0010","0011","0100","0101","0110","0111"]

This gets input for a decimal number

num = input("Decimal: ")

This initializes the required output (i.e. BCD value)  to an empty string

BCDValue = ""

This initializes valid input to True (Boolean)

valid = True

This iterates through the input string

for i in range(len(num)):

This checks if each character of the string is a number

   if num[i].isdigit():

If yes, it checks if the number ranges from 0 to 7 (inclusive)

       if(int(num[i])>= 0 and int(num[i])<8):

If yes, the corresponding BCD value is calculated

           BCDValue += BCD[i]+" "

       else:

If otherwise, then the input string is invalid and the loop is exited

<em>            valid = False</em>

<em>            break;</em>

If otherwise, then the input string is invalid and the loop is exited

<em>    else:</em>

<em>        valid = False</em>

<em>        break;</em>

If valid is True, then the BCD value is printed

<em>if(valid):</em>

<em>    print(BCDValue)</em>

If otherwise, it prints Invalid

<em>else:</em>

<em>    print("Invalid")</em>

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