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White raven [17]
3 years ago
13

What is this answer Y= 3x - 4

Mathematics
1 answer:
zubka84 [21]3 years ago
6 0
Which question exactly?
You might be interested in
What is the slope of a line parallel to the line whose equation is 4x-y=-4
HACTEHA [7]

Answer:

-y= -4x -4

y= 4x +4

slope is 4

Step-by-step explanation:

8 0
3 years ago
How are the solutions to the following two equations related m+5=72 <br> m+72=5
EastWind [94]
To see how they are related, let us solve the two equations.

FIRST EQUATION

m + 5 = 72

\rightarrow \: m = 72 - 5

\rightarrow \: m = 67

SECOND EQUATION

m + 72 = 5

\rightarrow \: m = 5 - 72

\rightarrow \: m = - 67

Hence the solutions to the two equations are ADDITIVE INVERSE of each other.
6 0
4 years ago
30 multiplied by what number would give me the letter (y), 30 multiplicado por que numero me daria la letra (y),
LiRa [457]
Thats like geometry 
and are you good in this suject?
5 0
3 years ago
A triangle has base 2x+1 and height 6x-3. What value of x would give an area of 240m2?
GREYUIT [131]

Answer:

The values of x which would give an area of 240m² would be:

x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}

Step-by-step explanation:

Given

The base of triangle b = 2x+1

The height of triangle h = 6x-3

The Area of the triangle A = 240 m²

The Area of the triangle has the formula

A = 1/2 × b × h

substituting b = 2x+1, h = 6x-3 and A = 240

240\:=\:\frac{1}{2}\:\left(2x+1\right)\:\times \left(6x-3\right)

480=\left(2x+1\right)\left(6x-3\right)

480=12x^2-3

Subtract 480 from both sides

12x^2-3-480=480-480

12x^2-483=0

3\left(4x^2-161\right)=0

3\left(2x+\sqrt{161}\right)\left(2x-\sqrt{161}\right)=0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

2x+\sqrt{161}=0\quad \mathrm{or}\quad \:2x-\sqrt{161}=0

solving

2x+\sqrt{161}=0

2x=-\sqrt{161}

Divide both sides by 2

\frac{2x}{2}=\frac{-\sqrt{161}}{2}

x=-\frac{\sqrt{161}}{2}

also solving

2x-\sqrt{161}=0

2x=\sqrt{161}

Divide both sides by 2

\frac{2x}{2}=\frac{\sqrt{161}}{2}

x=\frac{\sqrt{161}}{2}

Therefore, the values of x which would give an area of 240m² would be:

x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}

3 0
3 years ago
&gt;: If the scale factor is a 1. What happens to the shape? How can you prove this?
maria [59]
The shape would be exactly the same because any number multiplied by 1 equals itself.
3 0
3 years ago
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