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morpeh [17]
3 years ago
10

NEED HELP!!! I DON"T UNDERSTAND HOW TO FILL THIS IN. WILL MARK BRAINLIEST FOR THE BEST ANSWER!!!

Mathematics
1 answer:
Gnoma [55]3 years ago
4 0
I think the answer is:
Rectangle: X X O X X
Rhombus: X X X X O
Square: X X X X X
I hope you got a good grade!!!
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What is the least common denominator of 3/12 and 3/8 rename each fraction in the pair.
Alona [7]
24. 8x3=24
12x2=24
It would be 6/24 (3/12) and 9/24 (3/8)
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2

Step-by-step explanation:

I hope this helps!

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7.28
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The ratio of cookies to glasses of milk is 3:1. If there are 25 glasses of milk, how many cookies are there?
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Let V be a vector space of dimension 4. Determine if each statement is true or false. (a) Any set of 5 vectors in V must be line
son4ous [18]

Answer:

a) True

b) False

c) False

d) False

e) True

Step-by-step explanation:

a) Each basis of V has four vectors. Then any set of 5 vectors must be linear dependent (LD).

b) Suppose that \{v_1,v_2,v_3,v_4\} is a basis of V. Considere the set A=\{v_1,\lambda_1v_1,\lambda_2v_1,v_2,v_3\} where \lambda_1, \lambda_2 are scalars. The set has 5 vectors but V\neq span(A) because v_4 is not belong to A and v_4  is linear independent of v_1

c)  Suppose that \{v_1,v_2,v_3,v_4\} is a basis of V. Considere the set A=\{v_1,\lambda_1v_1,\lambda_2v_1,\lambda_3v_1\} where \lambda_1, \lambda_2,\lambda_3 are scalars. A has four nonzero vectors but isn't a basis because is a LD set.

d)  Suppose that \{v_1,v_2,v_3,v_4\} is a basis of V. Considere the set A=\{v_1,\lambda_1v_1,\lambda_2v_1\} where \lambda_1, \lambda_2 are scalars. A has 3 nonzero vectors but isn't a basis because is a LD set.

e)  Since any basis of V must have 4 elements, then a set of three vectors cannot generate V.

4 0
3 years ago
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