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maks197457 [2]
4 years ago
10

Kyra is using rectangular tiles of two types for a floor design. A tile of each type is shown below: Two rectangular tiles, rect

angle PQRS with vertices at P 5, 7. Q is at 9, 7. R is at 9, 12. S is at 5, 12 . Rectangle JKLM with vertices J 4, 5. K is at 6, 5. L is at 6, 10. M is at 4, 10. Which statement is correct? The two tiles are not similar because segment PQ is to segment QR is 4:5 and segment JK is to segment LM is 2:1. The two tiles are not similar because segment SP is to segment SR is 5:4 and segment MJ is to segment ML is 5:2. The two tiles are similar because segment PQ is to segment QR is 4:5 and segment JK is to segment KL is also 4:5. The two tiles are similar because segment SR is to segment ML is 2:1 and segment PQ is to segment JK is also 2:1.

Mathematics
2 answers:
Dovator [93]4 years ago
3 0
Hello,
Please, see the attached file.
Thanks.

7nadin3 [17]4 years ago
3 0
<span>The statement which is correct is the second option which is the two tiles are not similar because segment SP is to segment SR is 5:4 and segment MJ is to segment ML is 5:2. SP/SR=5/4 and MJ/Ml=5/2</span>
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krok68 [10]
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3 years ago
E 4) In the diagram below, the dimensions of the large rectangle are (3x-1) by (3x+7) units. The dimensions of the cut-out recta
frutty [35]

Answer:

Option (D)

Step-by-step explanation:

Area of a rectangle = Length × width

Area of large rectangle = (3x - 1)(3x + 7) square units

                                       = (9x² + 21x - 3x - 7)

                                       = 9x² + 18x - 7

Area of small rectangle = (2x + 5)x

                                       = (2x² + 5x) square units

Area of the shaded region = Area of large rectangle - Area of small rectangle

= (9x²+ 18x - 7) - (2x² + 5x)

= (9x² - 2x²) + (18x - 5x) - 7

= (7x² + 13x - 7) square units

Therefore, Option (D) will be the correct option.

4 0
3 years ago
Can smbdy help me???
Sergio [31]

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Answer:

  a.  One solution

Step-by-step explanation:

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__

<em>Additional comment</em>

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3 0
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3 years ago
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Vesnalui [34]

Answer:

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The 6-mile legs are a and b. c is the hypotenuse.

(6 mi)^2 + (6 mi)^2 = c^2

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c = sqrt(72) mi

c = sqrt(36 * 2) mi

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c = 8.5 mi

8 0
3 years ago
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