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Answer:
NaZ + H2O <----> HZ + OH-
[OH-] = [HZ]
[NaZ] = 0.15 M
pH = 10.7, so the pOH = 14-10.7 = 3.3; [OH-] = 10^-3.3 = 5.01E-4
kb = [OH-][HZ]/[NaZ] = (5.01E-4)^2/0.15 = 1.67E-6
ka = kw/kb = 1E-14/1.67E-6 = 5.99E-9 = 6.0E-9
Answer:
V₂ = 1866.32 mL
Explanation:
Given data:
Initial temperature = 27.8°C (27 + 273.15 K = 300.15 k)
Initial volume = 1500 mL
Final volume = ?
Final temperature = 100.0°C (100.0 + 273.15 K = 373.15 K)
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
1500 mL / 300.15 k = V₂ / 373.15 K
V₂ = 1500 mL× 373.15 K/ 300.15 k
V₂ = 560175 mL. K /300.15 k
V₂ = 1866.32 mL
Answer:
The mass of Mg consumed is 23.76 g.
Explanation:
Magnesium and nitrogen react as : three moles of magnesium reacts with one mole of nitrogen to give one mole of magnesium nitride.
as given that the mass of nitrogen reacted = 9.27 g
moles of nitrogen reacted = 
Thus moles of magnesium reacted = 3 X 0.33 = 0.99 moles
mass of Mg reacted = moles X atomic mass = 0.99 X 24 = 23.76 grams
