Question

So2 (5.00 g) and co2 (5.00 g) are placed in a 750.0 ml container at 50.0 °c. the partial pressure of so2 in the container was __________ atm.

Answer 1

SO2 (5.00 g) and CO2 (5.00 g) are placed in a 750.0 ml container at 50.0 °C. the partial pressure of SO2 in the container was 2.762 atm.

Further explanation

To calculate the partial pressure, we can calulate the total pressure

$Total pressure = \frac{nRT}{V} SO2 + \frac{nRT}{V} CO2$

Where:

• n is the number of moles
• R is the general gas constant $= 0.0821 L.atm/K.mole$
• T is the temperature in Kelvin
• V is the total volume

The amount of SO2 is n SO2 = mass/molar mass = m/M = $\frac{5 }{32} + 16*2 = 0.078125$ mol

The amount of CO2 is n CO2 = mass/molar mass = m/M = $\frac{5}{14} + 16*2 = 0.1$ mol

Total amount of gas is n(total) = $n1 + n2 = 0.078 + 0.113 = 0.191$  mol

T = 50+273 = 323 K

$V = \frac{750}{1000} = 0.75$liters

Total Pressure  $p*V = n*R*T$

Total Pressure $= (0.078125*0.0821*\frac{323}{0.75} ) + (0.1*0.0821*\frac{323}{0.75}) = 2.7623 + 3.535 = 6.298$ atm

Partial pressure = x SO2 * Total Pressure = $(\frac{no. of moles of SO2 }{total no. of moles} ) * Total pressure = (\frac{0.078125}{0.078125} +0.1) * 6.298 = 2.762$atm

Learn more

1. Learn more about  the partial pressure brainly.com/question/10503509
2. Learn more about  the container brainly.com/question/3238396
3. Learn more about The mole fraction brainly.com/question/6617005

Answer details

Grade:  9

Subject:  chemistry

Chapter:  pressure

Keywords:   the container, the partial pressure, SO2, CO2,  The mole fraction

Answer 2

To calculate the partial pressure, we have to calulate the total pressure first.
Total pressure = (nRT/V)SO2 + (nRT/V)CO2
n is the number of moles
R is the general gas constant = 0.0821 L.atm/K.mole
T is the temperature in Kelvin
V is the total volume
n SO2 = mass/molar mass = 5/ 32 + 16*2 = 0.078125
n CO2 = mass/molar mass = 5/14+ 16*2 = 0.1
T = 50+273 = 323K
V = 750/1000 = 0.75 liters
Total Pressure = (0.078125*0.0821*323/0.75) + (0.1*0.0821*323/0.75) = 2.7623 + 3.535 = 6.298 atm
Partial pressure = x SO2 * Total Pressure = (no. of moles of SO2 / total no. of moles) * Total pressure = (0.078125/0.078125+0.1) * 6.298 = 2.762 atm.