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Bess [88]
2 years ago
12

What is the process of breaking down food so that it can be used by living things??​

Chemistry
1 answer:
Darya [45]2 years ago
4 0

I think the answer you're looking for is digestion.

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(a) The absorbance of mixture at 400 nm was 0.40.
laiz [17]

Answer:

0.1 g/dl

Explanation:

The standard curve is a graph that relates the absorbance at 400 nm with the concentration of haemoglobin in mg/dl. To obtain the concentration from the absorbance value, we enter in the x-axis (absorbance at 400 nm) with the value 0.40 (the line between 0.2 and 0.6), we extrapolate the line to the curve and read the correspondent value on y-axis (concentration in mg/dl): 100 mg/dl.

So, we convert the concentration from mg/dl to g/dl by dividing into 1000:

100 mg/dl x 1 g/1000 mg = 0.1 g/dl

Therefore, the concentration of haemoglobin of the patient is 0.1 g/dl.

6 0
2 years ago
A sample of oxygen has a volume of 128 milliliter at a pressure of 500.0 mmhg calculate the volume this sample would occupy at s
leva [86]

Answer:

84.2mL

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 128mL

Initial pressure (P1) = 500mmHg

Final pressure (P2) = stp = 760mmHg

Final volume (V2) =..?

Thus, the new volume of the gas can be obtained by using the Boyle's law equation as follow:

P1V1 = P2V2

500 x 128 = 760 x V2

Divide both side by 760

V2 = (500 x 128)/760

V2 = 84.2mL

Therefore, the new volume of the gas is 84.2mL

4 0
3 years ago
Select all of the following statements that are incorrect.
lesantik [10]
A and c are incorrect
4 0
3 years ago
A 4.000 g sample of iron was heated from 0.0°C to 21.0°C. If it has a specific heat of 0.440 kJ/kg °C, how many kilojoules of he
Mashutka [201]
M = 4 g = 4/1000 kg = 0.004 kg, θ₂ = 21.0°C, θ₁ = 0°C , c = 0.44kJ/kg°C,

Q = mc(θ₂ - θ₁)

Q = 0.004*0.440*(21 - 0)

Q  =  0.03696 kJ 

0.03696 kJ<span> of heat is absorbed.</span>
6 0
3 years ago
Which element is a gas at STP?<br> 1)sulfur<br> 2)xenon<br> 3)potassium<br> 4)phosphorus
natulia [17]
I believe the answer is xenon
4 0
2 years ago
Read 2 more answers
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