Answer:
D ez
Step-by-step explanation:
Answer:
114 cm²
Step-by-step explanation:
Area of shaded region
= area of circle -area of square

Given that radius= 10cm, r= 10cm.

Let the length of a side of the square be x cm.
Applying Pythagoras Theorem,
10² +10²= x²
100 +100= x²
x²= 200

Area of square
= x²
= 200cm²
Area of shaded region
= 3.14(10²) -200
= 3.14(100) -200
= 314 -200
= 114 cm²
To have a different rectangle with the same perimeter you just have different measurements. If you need an example let me know!
Answer:
Yes, △ABC ∼ △FED by AA postulate.
Step-by-step explanation:
Given:
Two triangles ABC and FED.
m∠A = m∠B
m∠C = m∠A + 30°
m∠E = m∠F = 
m∠D =
°.
Now, let m∠A = m∠B = 
So, m∠C = m∠A + 30° = 
Now, sum of all interior angles of a triangle is 180°. Therefore,
m∠A + m∠B + m∠C = 180

Therefore, m∠A = 50°, m∠B = 50° and m∠C = m∠A + 30° = 50 + 30 = 80°.
Now, consider triangle FED,
m∠D+ m∠E + m∠F = 180

Therefore, m∠F = 50°
m∠E = 50° and
m∠D = 
So, both the triangles have congruent corresponding angle measures.
m∠A = m∠F = 50°
m∠B = m∠E = 50°
m∠C = m∠D = 80°
Therefore, the two triangles are similar by AA postulate.