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11111nata11111 [884]
2 years ago
10

In a lab experiment, the decay of a radioactive isotope is being observed. At the beginning of the first day of the experiment t

he mass of the substance was 1300 grams and mass was decreasing by 6% per day. Determine the mass of the radioactive sample at the beginning of the 8th day of the experiment. Round to the nearest tenth (if necessary).
Mathematics
2 answers:
FinnZ [79.3K]2 years ago
8 0

Answer:

843

Step-by-step explanation:

it says its right

dimaraw [331]2 years ago
5 0
Answer:
a13=310.7
Step-by-step explanation:
Formula= an=a1r^n-1
a13=1100(0.9)13-1
a13=310.7



Ps: I hoped this helps ✌️!
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For what values of m does the graph of y = 3x2 + 7x + m have two x-intercepts
Irina18 [472]

we are given

y=3x^2+7x+m

To find x-intercept means we have to find zeros

and for finding zeros , we will use quadratic formula

and we have it has two x-intercepts

so, it's discriminant must be greater than 0

so, we will find discriminant

D=\sqrt{b^2-4ac}

now, we can compare with

y=ax^2+bx+c

y=3x^2+7x+m

and then we can find a , b and c

a=3,b=7,c=m

now, we can find D

D=\sqrt{7^2-4*3*m}

D=\sqrt{49-12m}

It has two x-intercepts

so,

D=\sqrt{49-12m}>0

now, we can solve for m

49-12m>0

12m

m............Answer

8 0
3 years ago
Read 2 more answers
Can someone answer each step of this correctly?
Burka [1]

About Slope - Intercept Form:

  • y = mx + b
  • m is the slope
  • b is the y-intercept

About Standard Form:

  • Ax + By = C
  • A & B & C are integers
  • A & B are both non-zero
  • This form is good to use when wanting to find the x & y intercepts of a line

About Point - Slope Form:

  • Y - Y1 = m (x -X1)
  • Y1 & X1 is a point on the line
  • The form allows you to identify the slope & the point on the line

Other Info:

  • Remember, y comes before the x  
  • An ordered pair from your problem: (-3,1), -3 is x & 1 is y & x is before the y
  • An ordered pair from your problem: (3,5), 3 is x & 5 is y & x is before the y
  • For the graph, the vertical line is y
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Hope this information helps!!! :)


5 0
3 years ago
Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be
Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of t=0.6482

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

h(t)=-16t^2 +v_{o}t+s       Eqn(1).

Where:

h(t) : is the height range as a function of time

v_{o}   : is the initial velocity

s     : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

h(t)=-16t^2 + v_{o}t + 40        Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

<u>Ben:</u>

We know that v_{o}=60ft/s

Thus Eqn. (2) becomes:

h(t)=-16t^2+60t+40        Eqn.(3)

<u>Josh:</u>

We know that v_{o}=48ft/s

Thus Eqn. (2) becomes:

h(t)=-16t^2+48t+40       Eqn. (4).

<em><u>Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at </u></em>h(t)=0<em><u>. Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one. </u></em>

Thus we have for Ben, Eqn. (3) gives:

h(t)=0-16t^2+60t+40=0

Using the quadratic expression to find the roots of the quadratic we have:

t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec

Since time can only be positive we reject the t_{2} solution and we keep that Ben's book took t=4.3276 seconds to reach the ground.

Similarly solving for Josh we obtain

t_{1}=3.6794sec\\t_{2}=-0.6794sec

Thus again we reject the negative and keep the positive solution, so Josh's book took t=3.6794 seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482

So to answer the original question:

<em>Whose textbook reaches the ground first and by how many seconds?</em>

  • Josh's textbook reached the ground first
  • Josh's textbook reached the ground first by a difference of t=0.6482

3 0
3 years ago
What is the slope? (IXL)
andrey2020 [161]

Answer:

1/3

Step-by-step explanation:

rise over run

6 0
3 years ago
Fifteen more than half a number is 9.
7nadin3 [17]

Answer:

-12

Step-by-step explanation:

-12/2 = -6

-6+15 = 9

4 0
3 years ago
Read 2 more answers
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