Question

For this heterogeneous system 2 A ( aq ) + 3 B ( g ) + C ( l ) − ⇀ ↽ − 2 D ( s ) + 3 E ( g ) the concentrations and pressures at equilibrium are [ A ] = 9.68 × 10 − 2 M , P B = 9.54 × 10 3 Pa , [ C ] = 14.64 M , [ D ] = 10.11 M , and P E = 9.56 × 10 4 torr . Calculate the thermodynamic equilibrium constant, K.

Answer 1

Answer:

$2.55*10^{11$

Explanation:

Equation for the heterogeneous system is given as:

$2A_{(aq)} + 3 B_{(g)} + C_{(l)}$      ⇄      $2D_{(s)}$    $+$     $3E_{(g)}$

The concentrations and pressures at equilibrium  are:

$[A] = 9.68*10^{-2}M$

$P_B = 9.54*10^3Pa$

$[C]=14.64M$

$[D]=10.11M$

$P_E=9.56*10^4torr$

If we convert both pressure into bar; we have:

$P_B = 9.54*10^3Pa$

$P_B = (9.54*10^3)*\frac{1}{10^5} bar$

$P_B=9.54*10^{-2}bar$

$P_E=9.56*10^4torr$

1 torr = 0.001333 bar

$9.54*10^4 *0.001333 = 127.5 bar$

$K=\frac{[P_E]^3}{[A]^2[P_B]^3}$

$K=\frac{(127.5)^3}{(9.68*10^{-2})^2(9.54*10^{-2})^3}$

$K=2.55*10^{11$