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GaryK [48]
3 years ago
9

For this heterogeneous system 2 A ( aq ) + 3 B ( g ) + C ( l ) − ⇀ ↽ − 2 D ( s ) + 3 E ( g ) the concentrations and pressures at

equilibrium are [ A ] = 9.68 × 10 − 2 M , P B = 9.54 × 10 3 Pa , [ C ] = 14.64 M , [ D ] = 10.11 M , and P E = 9.56 × 10 4 torr . Calculate the thermodynamic equilibrium constant, K.
Chemistry
1 answer:
maw [93]3 years ago
3 0

Answer:

2.55*10^{11

Explanation:

Equation for the heterogeneous system is given as:

2A_{(aq)}  + 3 B_{(g)} + C_{(l)}      ⇄      2D_{(s)}    +     3E_{(g)}

The concentrations and pressures at equilibrium  are:

[A] = 9.68*10^{-2}M

P_B = 9.54*10^3Pa

[C]=14.64M

[D]=10.11M

P_E=9.56*10^4torr

If we convert both pressure into bar; we have:

P_B = 9.54*10^3Pa

P_B = (9.54*10^3)*\frac{1}{10^5} bar

P_B=9.54*10^{-2}bar

P_E=9.56*10^4torr

1 torr = 0.001333 bar

9.54*10^4 *0.001333 = 127.5 bar

K=\frac{[P_E]^3}{[A]^2[P_B]^3}

K=\frac{(127.5)^3}{(9.68*10^{-2})^2(9.54*10^{-2})^3}

K=2.55*10^{11

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