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Then if I have 210.1 g barium chloride with 45g potassium...how many grams of potassium chloride will I produce?

Katarina [22]

Answer:

85.8 g

Explanation:

The molar mass of BaCl₂ is 208.233 g/mol, so 210.1 g is about ...

210.1/208.233 ≈ 1.009 mol

The molar mass of K is about 39.089 g/mol, so 45 g is about ...

45/39.089 ≈ 1.1509 mol

The balanced equation seems to be ...

BaCl₂ + 2K ↔ 2KCl + Ba

This reaction requires 2 moles of potassium for each mole of barium chloride, so the available potassium limits the reaction. The result is as many moles of potassium chloride as there are moles of potassium.

The 1.1509 moles of KCl, at 74.551 g/mol will have a mass of about 85.8 g.

The reaction produces 85.8 g of KCl.

8 0

3 years ago

Read 2 more answers

A glucose solution is administered intravenously into the bloodstream at a constant rate r. As the glucose is added, it is conve

Helen [10]

Answer:

$C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}$

Explanation:

The differential equation is given as:

$\frac{dC}{dt} = r- kC$

$\frac{dC}{r- kC} = dt$

Taking integral of both sides; we have:

$\int\limits \frac{dC}{r- kC} = \int\limits dt$

$-\frac{1}{k} In(r-kC) = t+D\\In(r-kC)=-kt-kD$

$r-kC=e^{-kt-kD}$

$r-kC=e^{-kt}e^{-kD}$

$r-kC=Ae^{-kt}$

$kC=r-Ae^{-kt}$

$C=\frac{r}{k}-\frac{A}{k}e^{-kt}$

$C(t)=\frac{r}{k}-\frac{A}{k}e^{-kt}$ ------- equation (1)

If C(0)= $C_o$ ; we have:

C(0)= $\frac{r}{k}-\frac{A}{k}e^0$ (where; A is an integration constant)

$C_o = \frac{r}{k}- \frac{A}{k}$

$C_o=\frac{r-A}{k}$

$kC_o=r-A$

$A=r-kC_o$

Substituting $A=r-kC_o$ into equation (1); we have;

$C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}$

3 0

3 years ago

What were the defects in Ruther Ford Atomic model?

juin [17]

the RutherFord atomic model has the limitations in explaining the stability of the atom and the stability of the electron.

Explanation:

As we know basically the atom comprises of the positively charged proton and negative charge electron and no charge neutron.
In these particles, electron revolves with the nucleus as a centre in the orbit with the different energy levels.
So by this revolving action, there will be the loss of energy and thus electrons are to be falling into the nucleus which affects the stability of the electron.
The atom is said to be neutral electrically if the protons and electrons are equal. So in the above case if the electrons on losing the energy if it fells into the nucleus, as a result, the stability of the atom is affected which makes the atom as ions.

7 0

3 years ago

Please check if i did it right. did i put the right electric charge

Amiraneli [1.4K]

Yes it’s correct your answer connect with eachother I did this before

3 0

3 years ago

A sample of a pure compound that weighs 60.3 g contains 20.7 g Sb (antimony) and 39.6 g F (fluorine). What is the percent compos

Volgvan

Answer:

The percent composition of fluorine is 65.67%

Explanation:

Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.

That is, the percentage composition is the percentage by mass of each of the elements present in a compound.

The calculation of the percentage composition of an element is made by:

$percent composition element A=\frac{total mass of element A}{mass of compound} *100$

In this case, the percent composition of fluorine is:

$percent composition of fluorine=\frac{39.6 g}{60.3 g} *100$

percent composition of fluorine= 65.67%

The percent composition of fluorine is 65.67%

4 0

4 years ago