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Sidana [21]
3 years ago
10

Calculate the volume of a sample of aluminum that has a mass of 3.057 kg. The density of aluminum is 2.70 g/cm3 (taking into con

sideration the rounded to three significant figures)
Chemistry
1 answer:
Misha Larkins [42]3 years ago
3 0

Answer:

v = 1130 cm³

Explanation:

Given data:

Volume of sample = ?

Mass of Al sample = 3.057 Kg (3.057 Kg× 1000g/1 Kg = 3057g)

Density of Al sample = 2.70 g/cm³

Solution:

Formula:

d = m/v

d = density

m = mass

v= volume

by putting values

2.70 g/cm³ = 3057g /v

v = 3057g /2.70 g/cm³

v = 1130 cm³

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It is an endothermic process
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3 years ago
How many grams of gas must be released from a 32.0 L sample of CO2(g) at STP to reduce the volume to 16.6 L at STP?
Hoochie [10]

Answer:

30.3 g

Explanation:

At STP, 1 mol of any gas will occupy 22.4 L.

With the information above in mind, we <u>calculate how many moles are there in 32.0 L</u>:

  • 32.0 L ÷ 22.4 L/mol = 1.43 mol

Then we <u>calculate how many moles would there be in 16.6 L</u>:

  • 16.6 L ÷ 22.4 L/mol = 0.741 mol

The <u>difference in moles is</u>:

  • 1.43 mol - 0.741 mol = 0.689 mol

Finally we <u>convert 0.689 moles of CO₂ into grams</u>, using its <em>molar mass</em>:

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6 0
3 years ago
What were some reasons why it was a good idea to remove the lid from the separatory funnel after each extraction? Select all tha
masya89 [10]
Liquid will no pour out. At the bottom the separating funnel consists of a valve it allow the liquid to flow out.The lid is on the top to pour in liquid from the top,it is air tight. Therefore as long as the lid is put, the liquid will not flow out at the bottom. The reason is that ,the incoming air has no way to get into the flask.
3 0
3 years ago
What pressure is required to compress 196.0 liters of air at 1.83 atmosphere into a cylinder whose volume is 26.0 liters
drek231 [11]

Answer:

P₂ = 13.79 atm

Explanation:

Given data:

Initial volume = 196.0 L

Initial pressure = 1.83 atm

Final volume = 26.0 L

Final pressure = ?

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.83 atm × 196.0 L = P₂× 26.0 L

P₂ = 358.68 atm. L /  26.0 L

P₂ = 13.79 atm  

5 0
3 years ago
How many moles are present in a 5.8 g sample of copper?
Oksanka [162]

Explanation:

Molar mass of Cu = 63.5g/mol

Moles of Cu

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8 0
2 years ago
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