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4 years ago

What is 21.2264 rounded to the nearest tenths

Mathematics

2 answers:

zalisa [80]4 years ago

5 0

Answer:

it is 21.2

Step-by-step explanation:

Nuetrik [128]4 years ago

4 0

Answer: 21.4

Step-by-step explanation: Step 1. I look in the hundredths place. If I see a 5 or more I round up, otherwise down, to the next multiple of one tenth.

Step 2. The number in the hundredths place is 5 so I know to round up.

Step 3. The next higher multiple of one tenth is 21.4. That is the answer.

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A conducter is mapping a trip and records the distance the trian travels over a certain time intervals

jeyben [28]

Answer:

cool

Step-by-step explanation:

6 0

3 years ago

How does one solve for the n+1st term with the nth term of a sequence

love history [14]

Answer:

<h3>The answer is option B</h3>

Step-by-step explanation:

The nth term of the sequence is

A(n) = 5n + 7

To find the (n+1)st term substitute n+1 into the general equation

That's

For (n + 1)st term

A(n+1) = 5(n+ 1) + 7

A(n+1) = 5n + 5 + 7

Hope this helps you

4 0

3 years ago

Read 2 more answers

Expand the following expression −7(5x−8)

KonstantinChe [14]

-7(5x-8)
=-35x + 56

which is basically 56-35x if u swap it around

6 0

3 years ago

Read 2 more answers

Please find the perimeter and area of these shapes

ladessa [460]

Answer:

ABC shaded area = 36 $\pi$ - 72 cm²

ABC shaded area perimeter = $6\pi +12\sqrt{2}$ cm

ABCD area = $\dfrac52 \pi$ cm²

ABCD perimeter = $3\pi +2$ cm

Step-by-step explanation:

Shape ABC

Assuming you want the area and perimeter of the shaded part of the shape only...

Area

Area of a sector = $\dfrac12r^2\theta$ (where r is the radius and $\theta$

⇒ area of a sector = $\dfrac12 \times 12^2\times \dfrac{\pi}{2} =36\pi \ \textsf{cm}^2$

Area of triangle = 1/2 x base x height

⇒ area of triangle = 1/2 x 12 x 12 = 72 cm²

Therefore, area of shaded area = area of sector - area of triangle

⇒ area = 36 $\pi$ - 72 cm²

Perimeter

Arc length = $r\theta$ (where r is the radius and $\theta$

⇒ arc length = $12\times\dfrac12\pi =6\pi \ \textsf{cm}$

Hypotenuse of triangle = $\sqrt{a^2+b^2}$ (where a and b are the legs of the right triangle)

⇒ hypotenuse = $\sqrt{12^2+12^2} =12\sqrt{2}$ cm

Therefore, perimeter = arc length + hypotenuse

⇒ perimeter = $6\pi +12\sqrt{2}$ cm

Shape ABCD

Area

Area of a semicircle = $\dfrac12 \pi r^2$ (where r is the radius)

⇒ area of large semicircle ABC = $\dfrac12 \times \pi \times 2^2=2\pi \ \textsf{cm}^2$

⇒ area of small semicircle AD = $\dfrac12 \times \pi \times 1^2=\dfrac12\pi \ \textsf{cm}^2$

⇒ area of shape ABCD = $\dfrac12 \pi + 2 \pi=\dfrac52 \pi \ \textsf{cm}^2$

Perimeter

1/2 circumference = $\pi r$

⇒ perimeter = $2\pi +2+\pi=3 \pi+2 \ \textsf{cm}$

7 0

2 years ago

Henry runs each lap in 4 minutes. He will run at most 11 laps today. What are the possible numbers of minutes he will run today?

son4ous [18]

Answer:

44 Minutes

Step-by-step explanation:

If he takes for minutes per lap than some easy multiplication will do the job to find out how long 11 laps will take.

If he keeps running a lap in 4 minutes for every lap up, until the 11th lap, that means we multiply 11 times 4.

Another example being, if I run 1 lap in 1 minute then if I ran 2 laps it would take me 2 minutes, because 1 times 2 is 2, and so fourth for each lap. So if I ran 11 laps it would take me 11 minutes because 11 times 1 is 11.

3 0

3 years ago