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STatiana [176]
4 years ago
9

What is 21.2264 rounded to the nearest tenths

Mathematics
2 answers:
zalisa [80]4 years ago
5 0

Answer:

it is 21.2

Step-by-step explanation:

Nuetrik [128]4 years ago
4 0

Answer:  21.4

Step-by-step explanation: Step 1. I look in the hundredths place. If I see a 5 or more I round up, otherwise down, to the next multiple of one tenth.

Step 2. The number in the hundredths place is 5 so I know to round up.

Step 3. The next higher multiple of one tenth is 21.4. That is the answer.

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A conducter is mapping a trip and records the distance the trian travels over a certain time intervals
jeyben [28]

Answer:

cool

Step-by-step explanation:

6 0
3 years ago
How does one solve for the n+1st term with the nth term of a sequence
love history [14]

Answer:

<h3>The answer is option B</h3>

Step-by-step explanation:

The nth term of the sequence is

A(n) = 5n + 7

To find the (n+1)st term substitute n+1 into the general equation

That's

<u>For (n + 1)st term</u>

A(n+1) = 5(n+ 1) + 7

A(n+1) = 5n + 5 + 7

<h3>A(n+1) = 5n + 12</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
Expand the following expression −7(5x−8)
KonstantinChe [14]
-7(5x-8)
=-35x + 56

which is basically 56-35x if u swap it around
6 0
3 years ago
Read 2 more answers
Please find the perimeter and area of these shapes
ladessa [460]

Answer:

ABC shaded area = 36\pi - 72   cm²

ABC shaded area perimeter = 6\pi +12\sqrt{2}    cm

ABCD area = \dfrac52 \pi  cm²

ABCD perimeter = 3\pi +2   cm

Step-by-step explanation:

<u>Shape ABC</u>

Assuming you want the area and perimeter of the shaded part of the shape only...

<u>Area</u>

Area of a sector = \dfrac12r^2\theta (where r is the radius and \theta<em> </em>

⇒ area of a sector = \dfrac12 \times 12^2\times \dfrac{\pi}{2} =36\pi  \ \textsf{cm}^2

Area of triangle = 1/2 x base x height

⇒ area of triangle = 1/2 x 12 x 12 = 72 cm²

Therefore, area of shaded area = area of sector - area of triangle

⇒ area = 36\pi - 72 cm²

<u>Perimeter</u>

Arc length = r\theta (where r is the radius and \theta<em> </em>

⇒ arc length = 12\times\dfrac12\pi =6\pi  \ \textsf{cm}

Hypotenuse of triangle = \sqrt{a^2+b^2} (where a and b are the legs of the right triangle)

⇒ hypotenuse = \sqrt{12^2+12^2} =12\sqrt{2} cm

Therefore, perimeter = arc length + hypotenuse

⇒ perimeter = 6\pi +12\sqrt{2}  cm

<u>Shape ABCD</u>

<u>Area</u>

Area of a semicircle = \dfrac12 \pi r^2 (where r is the radius)

⇒ area of large semicircle ABC = \dfrac12 \times \pi \times 2^2=2\pi  \ \textsf{cm}^2

⇒ area of small semicircle AD = \dfrac12 \times \pi \times 1^2=\dfrac12\pi  \ \textsf{cm}^2

⇒ area of shape ABCD = \dfrac12 \pi + 2 \pi=\dfrac52 \pi \ \textsf{cm}^2

<u>Perimeter</u>

1/2 circumference = \pi r

⇒ perimeter = 2\pi +2+\pi=3 \pi+2 \ \textsf{cm}

7 0
2 years ago
Henry runs each lap in 4 minutes. He will run at most 11 laps today. What are the possible numbers of minutes he will run today?
son4ous [18]

Answer:

44 Minutes

Step-by-step explanation:

If he takes for minutes per lap than some easy multiplication will do the job to find out how long 11 laps will take.

If he keeps running a lap in 4 minutes for every lap up, until the 11th lap, that means we multiply 11 times 4.

<em>Another example being, if I run 1 lap in 1 minute then if I ran 2 laps it would take me 2 minutes, because 1 times 2 is 2, and so fourth for each lap. So if I ran 11 laps it would take me 11 minutes because 11 times 1 is 11.</em>

3 0
3 years ago
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