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belka [17]
4 years ago
10

Whenever 2 line or intersect at 90 the 2 lines are said to be ?

Mathematics
2 answers:
Sedaia [141]4 years ago
7 0
Two lines that intersect at 90 degrees are considered perpendicular to each other.

Lelechka [254]4 years ago
5 0
Perpendicular to each other.
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\left(3x-5\right)+\left(x+6\right)
ryzh [129]
I'm sorry but I couldn't really get that can u at least take a picture or something
5 0
3 years ago
Simplify (3х2 – 2) + (2х2 – бх + 3).
kolbaska11 [484]

Answer:

5x^2 -6x +1

Step-by-step explanation:

(3х^2 – 2) + (2х^2 – бх + 3).

Combine like terms

(3х^2  + 2х^2 – бх + 3-2)

5x^2 -6x +1

4 0
3 years ago
Given the domain (-2,2,4) what is the range for the relation 3x-y=3
Bumek [7]

Answer:

Given the domain, the range for 3x-y = 3 is {-9, 6, 9}

Step-by-step explanation:

First you have to put the relation in terms of y ⇒ 3x - y = 3⇒ 3x -3 = y

⇒ y = 3x - 3.

Then you replace the values indicated by the domain to find their "y" values (the ones that constitute the range).

f(-2) = -9

f(2) = 6

f(4) = 9.

Finally, the range for the given domain is {-9, 6, 9}

3 0
3 years ago
Find the 6 trìg functions
mars1129 [50]

I hope this helps you

let's find AB

AB=square root of 2^2+3^2

AB=square root of 13

cosO=2/sqrt13

sinO=3/sqrt13

tgO=3/2

ctgO=2/3

6 0
3 years ago
1. Work out the speed of a car travelling:
Norma-Jean [14]

Answer:

10m/s,15m/s,20m/s,5m/s

Step-by-step explanation:

Speed = distance / time

a) distance = 100m , time = 10s

Speed = distance / time

Speed = 100m/10s

Speed = 10m/s

b) distance = 300m , time = 20s

Speed = distance / time

Speed = 300m/20s

Speed = 15m/s

c) distance = 700m , time = 35s

Speed = distance / time

Speed = 700m/35s

Speed = 20m/s

d) distance = 1000m , time = 200s

Speed = distance / time

Speed = 1000m/200s

Speed = 5m/s

I hope this was helpful, please rate as brainliest  

7 0
3 years ago
Read 2 more answers
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