Find the volume of 22 ft

Mathematics

1 answer:

Scilla [17]3 years ago

7 0

This question is incomplete. There is no way to get a volume from a single
length

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Please help with this

Setler [38]

Answer:

x = 6

Step-by-step explanation:

The scale factor is

28/8 = 7/2

We take the ratio of the larger side over the smaller side

Using ratios we can find the sides

28 21

----- = ---------

8 x

Using cross products

28x = 21*8

28x =168

Divide each side by 28

28x/28 = 168/28

x =6

7 0

3 years ago

If these two figures are similar what is the measure of the missing side length J?

Ray Of Light [21]

If the long side on both is 9ft and 3ft then 3•3 is 9 so for the short side you do the same. If the short side is 1ft and the other is "j" then it's 1•3 is 3.

1•3=3
Sorry if it's confusing the way I explained it.

3 0

2 years ago

Use spherical coordinates. evaluate (9 − x2 − y2) dv, where h is the solid hemisphere x2 + y2 + z2 ≤ 4, z ≥ 0.

avanturin [10]

In spherical coordinates, we have

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}$

which gives volume element

$\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

and so the triple integral is given by

$\displaystyle\iiint_H(9-x^2-y^2)\,\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9-\rho^2\sin^2\varphi)\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$
$=\displaystyle2\pi\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9\rho^2\sin\varphi-\rho^4\sin^3\varphi)\,\mathrm d\rho\,\mathrm d\varphi$
$=\dfrac{592\pi}{15}$