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3 years ago

。find the solution of the system of equations shown on the graph. enter the correct answer

Mathematics

1 answer:

DochEvi [55]3 years ago

5 0

The solution would be the exact point where the lines meet which is at (-4,3)

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A silo is a composite of a cylindrical tower with a cone for a roof. Find the volume of the silo if the

xxMikexx [17]

Answer:

5127079.21 cubic feet

Step-by-step explanation:

The silo is in the shape of a cylinder and a cone.

The volume of the silo will be the sum of the volumes of the cylinder and the cone.

Therefore, its volume is:

$V = \pi r^2h + \frac{1}{3} \pi rH$

where r = radius of cylinder and cone

h = height of cylinder

H = height of cone

The radius of the base is 120 feet, the height of the roof (cone) is 25 feet. The height of the entire silo is 130 feet. This means that the height of the cylinder is:

130 - 25 = 105 feet

Therefore, the volume of the silo is:

$V = (\pi * 120^2 * 105) + (\frac{1}{3} * 120^2 * 25)\\\\V = 4750088.09 + 376991.12\\\\V = 5127079.21 ft^3$

The volume of the silo is 5127079.21 cubic feet.

3 0

2 years ago

jack obtains a loan of $4815.16 at 2.3% ordinary interest for 42 days. what is the maturity value of the loan

il63 [147K]

The maturity value is 4827 and if needed interest value is 12.

4 0

3 years ago

Special right triangles: what is the value of x? enter your answer in the box.

tiny-mole [99]

I think you meant to add more to your question (posting the specific problem).
In general, one special right triangle is the 45°-45°-90° triangle, in which both legs are congruent and the hypotenuse = √2 * the length of the leg. if you happen to not have the length of the leg, the formula for finding the leg is: leg = hypotenuse / √2

Another special right triangle is the 30°-60°-90° triangle. With this kind of triangle the length of the hypotenuse is twice the length of the shorter leg. The length of the longer leg is √3 times the length of the shorter leg.
hypotenuse = 2 * shorter leg
longer leg = √3 * shorter leg

7 0

3 years ago

A rubber ball is dropped from the top of a hole. Exactly 20 seconds later, the sound of the rubber ball hitting bottom is heard.

gayaneshka [121]

9514 1404 393

Answer:

4192.9 ft

Step-by-step explanation:

We assume your falling-distance formula is supposed to be ...

s = 16t²

So, the time required to fall distance s is ...

t = √(s/16) = (1/4)√s

The time required for sound to travel distance s is ...

s = 1100t

t = s/1100

Then the sum of the time for the ball to fall and the time for the sound to travel back is ...

(1/4)√s + s/1100 = 20

275√s = 22000 -s . . . . . multiply by 1100 and subtract s

75625s = s^2 -44000s +484,000,000 . . . square both sides

s^2 -119,625s +484,000,000 = 0 . . . . put in standard form

s ≈ (1/2)(119,625 ±√12,374,140,625) = {4192.943, 115432.057}

Only the smaller of these two solutions makes any sense in this problem.

The hole is about 4192.9 feet deep.

_____

Additional comment

The distance equation for the falling object presumes a vacuum. The sound transmission presumes the presence of air, so the question setup is self-contradictory.

7 0

3 years ago

Need help with this please.

iogann1982 [59]

Hi....

Im not sure if i got it right but i think its: 1.8........ Hope this helps. Brainliest Please

4 0

3 years ago

。find the solution of the system of equations shown on the graph. enter the correct answer ​

。find the solution of the system of equations shown on the graph. enter the correct answer