Question

5x-2y=-6 3x-4y = -26​

Answer 1

For this case we must solve the following system of equations:

$5x-2y = -6\\3x-4y = -26$

We multiply the first equation by -2:

$-10x + 4y = 12$

We add the new equation with the second one:

$-10x + 3x + 4y-4y = 12-26$

We have different signs subtracted and the sign of the major is placed:

$-7x = -14\\x = \frac {-14} {- 7}\\x = 2$

Now we find the value of the variable "y":

$3x-4y = -26\\3 (2) -4y = -26\\6-4y = -26\\-4y = -26-6\\-4y = -32\\y = \frac {-32} {- 4}\\y = 8$

Thus, the solution of the system is given by:

$(x, y) :( 2,8)$

Answer:

$(x, y) :( 2,8)$