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seraphim [82]
3 years ago
13

Is the law of conservation of mass valid during chemical reactions?

Chemistry
2 answers:
Elan Coil [88]3 years ago
7 0

YES LAW OF CONSERVATION OF MASS IS VALID DURING BECAUSE IT STATE THAT THE TOTAL MASS OF PRODUCTS MUST BE EQUAL TO THE TOTAL MASS OF REACTANT

liberstina [14]3 years ago
7 0
Law of Conservation of Mass is valid in everything!!!! Especially whenever science is involved
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Answer:A.) molecule of atoms forms

Explanation:

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Arrange the following in order of increasing bond strength of the carbon oxygen bond:
icang [17]

Answer: Option (d) is the correct answer.

Explanation:

It is known that length of a bond is inversely proportional to the bond strength. This also means that a single bond has long length due to which it is weak in nature.

And, a double bond is shorter in length and has more strength as compared to a single bond. Whereas a triple bond has the smallest length and it has high strength as compared to a double or single bond.

For example, carbon monoxide is CO where there is a triple bond between the carbon and oxygen atom.

Carbon dioxide is CO_{2} where there exists a double bond between the carbon and oxygen atom.

A carbonate ion is CO^{2-}_{3} when two oxygen atoms are attached through single bond with the carbon atom and another oxygen atom is attached through a double bond to the carbon atom.

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5 0
3 years ago
A hot metal plate at 150°C
Travka [436]
The air surrounding the hot plate would heat up through the process of convection
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3 years ago
Which among the following pairs are not isotopes?​
topjm [15]
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8 0
4 years ago
For a particular reaction at 298 K, the equilibrium constant is equal to 581. Determine ΔG° in kJ/mol for the reaction. Do not i
slava [35]

<u>Answer:</u> The standard Gibbs free energy of the reaction is -15.8 kJ/mol

<u>Explanation:</u>

Relation between standard Gibbs free energy and equilibrium constant follows:

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = Standard Gibbs free energy = ?

R = Gas constant = 8.314J/K mol

T = temperature = 298 K

K_{eq}  = equilibrium constant = 581

Putting values in above equation, we get:

\Delta G^o=-(8.314J/Kmol)\times 298K\times \ln (581)\\\\\Delta G^o=-15769.13J/mol=-15.8kJ/mol

Conversion factor used: 1 kJ = 1000 J

Hence, the standard Gibbs free energy of the reaction is -15.8 kJ/mol

4 0
3 years ago
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