corrected question:
Determining Density and Using Density to Determine Volume or Mass
(a) Calculate the density of mercury if 1.00 × 10 g occupies a volume of 7.36 cm³
(b) Calculate the volume of 65.0 g of liquid methanol (wood alcohol) if its density is 0.791 g/mL.
(c) What is the mass in grams of a cube of gold (density = 19.32 g/cm) if the length of the cube is 2.00 cm?
(d) Calculate the density of a 374.5-g sample of copper if it has a volume of 41.8 cm³ A student needs 15.0 g of ethanol for an experiment. If the density of ethanol is 0.789 g/mL, how many milliliters of ethanol are needed? What is the mass, in grams, of 25.0 mL of mercury (density = 13.6 g/mL)?
Answer:
density = 
ρ=m/v ,m=ρv, v=m/ρ
(a)m=1*10g , v=7.36cm³
ρ=10/7.36 =1.36g/cm³
(b) m=65g, ρ=0.791 g/mL.
v= 65/0.791 =82.17g/mL
(c) ρ=19.32g/cm³, l=2cm, v=l³=8cm³
m=19..32*8=154.56g/cm³
(d) mass of copper=374.5g , v=41.8cm³
ρ=374.5/41.8 =8.96g/cm³
mass of ethanol=15g, density of ethanol=0.789g/mL
v=15/0.789 =19.01mL
volume of mecury=25mL, density of mercury=13.6g/mL
m=25*13.6=340g
Answer:
V₂ = 2509.62 cm³
Explanation:
Given data:
Initial volume = 1500 cm³
Initial temperature = -65°C (-65 + 273 = 208 K)
Final temperature = 75°C ( 75 +273 = 348 K)
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 1500 cm³ × 348 K / 208 k
V₂ = 522000 cm³.K / 208 k
V₂ = 2509.62 cm³
It take more energy to break the bonds of the reactants and less energy is given off when the product bonds are formed.
<h3>What is Energy?</h3>
Energy is defined as the ability to do work. Work is done in the breaking or formation of bonds.
The standard Enthalpy (ΔH) of water which was formed in the given reaction is negative.
ΔH= Δproduct - Δreactant
This means that the energy to break the bonds of the reactants is more.
Read more about Enthalpy here brainly.com/question/14291557
Molar mass HNO₃ = 63.0 g/mol
number of moles = 3.94 / 63.0 => 0.0625 moles
Volume = moles / molarity
V = 0.0625 / 1.50
V = 0.04166 L x 1000 = 41.66 mL
hope this helps!
<h3>Further explanation</h3>
The basic oxide is an oxide-forming a base solution.
These oxides are mainly from group 1 alkaline and group 2-alkaline earth
If this oxide is dissolved in water it will form an alkaline solution
LO + H₂O --> L(OH)₂ ---> alkaline earth
L₂O + H₂O --> LOH --> alkaline
So the basic oxides : Na₂O and MgO
Na₂O + H₂O --> NaOH (sodium hydroxide, strong base)
MgO + H₂O --> Mg(OH)₂ (magnesium hydroxide, strong base)
The aqueous solution of CO₂ , obtained by dissolving CO₂ in water
CO₂ + H₂O --> H₂CO₃ (carbonic acid)
In general, basic oxide is obtained from metal oxide, while acid oxide is obtained from non-metal oxide
