Arrange the following in order of increasing bond strength of the carbon oxygen bond:
1 answer:
Answer: Option (d) is the correct answer.
Explanation:
It is known that length of a bond is inversely proportional to the bond strength. This also means that a single bond has long length due to which it is weak in nature.
And, a double bond is shorter in length and has more strength as compared to a single bond. Whereas a triple bond has the smallest length and it has high strength as compared to a double or single bond.
For example, carbon monoxide is CO where there is a triple bond between the carbon and oxygen atom.
Carbon dioxide is where there exists a double bond between the carbon and oxygen atom.
A carbonate ion is when two oxygen atoms are attached through single bond with the carbon atom and another oxygen atom is attached through a double bond to the carbon atom.
Hence, we can conclude that order of increasing bond strength of the given carbon oxygen bond is as follows.
Carbonate ion < carbon dioxide < carbon monoxide
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Answer : The value of for the reaction is +571.6 kJ/mole.
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given chemical reaction is,
Now we have to determine the value of for the following reaction i.e,
According to the Hess’s law, if we reverse the reaction then the sign of change.
So, the value for the reaction will be:
Hence, the value of for the reaction is +571.6 kJ/mole.
<u>Answer:</u> The mass percent of potassium bromide in the mixture is 9.996%
<u>Explanation:</u>
- To calculate the number of moles, we use the equation:
.....(1)
<u>For lead (II) bromide:</u>
Given mass of lead (II) bromide = 0.7822 g
Molar mass of lead (II) bromide = 367 g/mol
Putting values in equation 1, we get:
- The chemical equation for the reaction of lead (II) nitrate and potassium bromide follows:
By Stoichiometry of the reaction:
1 mole of lead (II) bromide is produced from 2 moles of potassium bromide
So, 0.0021 moles of lead (II) bromide will be produced from = of potassium bromide
- Now, calculating the mass of potassium bromide by using equation 1, we get:
Molar mass of KBr = 119 g/mol
Moles of KBr = 0.0042 moles
Putting values in equation 1, we get:
- To calculate the percentage composition of KBr in the mixture, we use the equation:
Mass of mixture = 5.000 g
Mass of KBr = 0.4998 g
Putting values in above equation, we get:
Hence, the percent by mass of KBr in the mixture is 9.996 %