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grigory [225]
3 years ago
6

Arrange the following in order of increasing bond strength of the carbon oxygen bond:

Chemistry
1 answer:
icang [17]3 years ago
5 0

Answer: Option (d) is the correct answer.

Explanation:

It is known that length of a bond is inversely proportional to the bond strength. This also means that a single bond has long length due to which it is weak in nature.

And, a double bond is shorter in length and has more strength as compared to a single bond. Whereas a triple bond has the smallest length and it has high strength as compared to a double or single bond.

For example, carbon monoxide is CO where there is a triple bond between the carbon and oxygen atom.

Carbon dioxide is CO_{2} where there exists a double bond between the carbon and oxygen atom.

A carbonate ion is CO^{2-}_{3} when two oxygen atoms are attached through single bond with the carbon atom and another oxygen atom is attached through a double bond to the carbon atom.

Hence, we can conclude that order of increasing bond strength of the given carbon oxygen bond is as follows.

        Carbonate ion < carbon dioxide < carbon monoxide

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In this experiment, we will be performing a titration with a buret. place the steps in order. 1. record the ph when 0.0 ml of na
77julia77 [94]

I am guessing that your solutions of HCl and of NaOH have approximately the same concentrations. Then the equivalence point will occur at pH 7 near 25 mL NaOH.

The steps are already in the correct order.

1. Record the pH when you have added 0 mL of NaOH to your beaker containing 25 mL of HCl and 25 mL of deionized water.

2. Record the pH of your partially neutralized HCl solution when you have added 5.00 mL of NaOH from the buret.

3. Record the pH of your partially neutralized HCl solution when you have added 10.00 mL, 15.00 mL and 20.00 mL of NaOH.

4. Record the NaOH of your partially neutralized HCl solution when you have added 21.00 mL, 22.00 mL, 23.00 mL and 24.00 mL of NaOH.

5. Add NaOH one drop at a time until you reach a pH of 7.00, then record the volume of NaOH added from the buret ( at about 25 mL).

6. Record the pH of your basic HCl-NaOH solution when you have added 26.00 mL, 27.00 mL, 28.00 mL, 29.00 mL and 30.00 mL of NaOH.

7. Record the pH of your basic HCl-NaOH solution when you have added 35.00 mL, 40.00 mL, 45.00 mL and 50.00 mL of NaOH from your 50mL buret.

4 0
3 years ago
What is the value of delta Hrxn for this equation:
Ratling [72]

Answer:

The ΔHrxn for the above equation = 179 kJ/mol

Explanation:

The reaction bond enthalpies are for the reactant;

3 × N-H = 3 × 390 = 1,170 kJ/mol

2 × O=O = 2 × 502 = 1004 kJ/mol

The reaction bond enthalpies are for the product;

3 × N-O = 3 × 201 = 603 kJ/mol

3 × O-H = 3 × 464 = 1,392 kJ/mol

The ΔHrxn for the above equation is therefore;

ΔHrxn = 1,170 + 1,004 - (603 + 1,392) = 179 kJ/mol

6 0
3 years ago
For the reaction of hydrogen with iodine
fenix001 [56]

Answer:

r_{H_2} = \frac{-1}{2} r_{HI}

Explanation:

Hello!

In this case, considering the given chemical reaction:

H_2(g) + I_2(g) \rightarrow 2HI(g)

Thus, by applying the law of rate proportions, we can write:

\frac{1}{-1} r_{H_2} = \frac{1}{-1}r_{i_2} = \frac{1}{2} r_{HI}

Whereas the stoichiometric coefficients of reactants are negative due their disappearance and that of the product is positive due to its appearance. In such a way, when we relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide, we obtain:

r_{H_2} = \frac{-1}{2} r_{HI}

Best regards!

8 0
3 years ago
Becky leaves home and rides a distance of 30 km. it took her 2.5 hours. what is her speed
Charra [1.4K]
Becky's speed is her distance travelled which is 30 km divided by her time travelled of 2.5 hours which gives her average speed of 12 km/hour which is a quite good speed if she was say riding a bicycle and which would give her a good aerobic workout. 
4 0
3 years ago
Standard temperature and pressure (STP), in the context of gases, refers to a) 298.15 K and 1 atm b) 273.15 K and 1 atm c) 298.1
lina2011 [118]

Answer : The correct option is, (B) 273.15 K and 1 atm

Explanation :

STP : STP stands for standard temperature and pressure.

STP conditions :

The temperature is, 0^oC or 273.15K or 32^oF

The pressure is, 1atm or 101.325kPa

The volume is 22.4 L for 1 mole of a substance.

Hence, the correct option is, (B) 273.15 K and 1 atm

7 0
3 years ago
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