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CaHeK987 [17]
3 years ago
7

need help plz !The reaction between hydrogen and nitrogen to give ammonium is a reversible reaction. if why or why not.Answer it

plz ​don't spam
Chemistry
2 answers:
Orlov [11]3 years ago
7 0

Answer:

<h3 /><h3>We get ammonia because the </h3><h3>forward and reverse reactions are happening at the same rates.</h3>

<h3>If 3 mol of H2 is mixed in a sealed vessel with 1 mol N2 under suitable conditions thenthey will react to form ammonia NH3 :</h3>

<h3>N2 + 3H2→ 2NH3</h3>

<h3>At the start of the reaction the concentration</h3><h3> of the </h3><h3>N2 and H2 are high. As soon as </h3><h3>some NH3 is formed the reverse reaction will start to occur:</h3><h3 /><h3>2NH3→N2+3H2</h3>

  • The rate of the reaction depends on concentration so the forward reaction will be fast at first when the concentration of the reactants is high. It will slow down as their concentration decreases.

  • By the same reasoning the reverse reaction will be slow at first then increase. These two processes continue until a point is reached when the rates of the forward and reverse reactions are equal.

  • We now state that the reaction has reached equilibrium which we show by:

  • N2+3H2⇌2NH3

It is described as "dynamic" because the forward and reverse reactions are happening at the same time although the concentrations of all the species remain constant.

So although NH3 is constantly breaking down, more is being formed at a constant rate.

In the Haber Process the system is actually not allowed to completely reach equilibrium as the process is continuous, as described in Mukhtar's answer.

MaRussiya [10]3 years ago
5 0

Answer:

We get ammonia because the forward and reverse reactions are happening at the same rates.

If 3 mol of  

H

2

is mixed in a sealed vessel with 1 mol  

N

2

under suitable conditions then they will react to form ammonia  

N

H

3

:

N

2

+

3

H

2

→

2

N

H

3

At the start of the reaction the concentration of the  

N

2

and  

H

2

are high. As soon as some  

N

H

3

is formed the reverse reaction will start to occur:

2

N

H

3

→

N

2

+

3

H

2

The rate of the reaction depends on concentration so the forward reaction will be fast at first when the concentration of the reactants is high. It will slow down as their concentration decreases.

By the same reasoning the reverse reaction will be slow at first then increase. These two processes continue until a point is reached when the rates of the forward and reverse reactions are equal.

We now state that the reaction has reached equilibrium which we show by:

N

2

+

3

H

2

⇌

2

N

H

3

It is described as "dynamic" because the forward and reverse reactions are happening at the same time although the concentrations of all the species remain constant.

So although  

N

H

3

is constantly breaking down, more is being formed at a constant rate.

In the Haber Process the system is actually not allowed to completely reach equilibrium as the process is continuous, as described in Mukhtar's answer.

Explanation:

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