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3 years ago

Consider the chemical equation below.

Chemistry

1 answer:

igor_vitrenko [27]3 years ago

7 0

Answer : The net ionic equation will be,

$2H^{+}(aq)+2OH^-(aq)\rightarrow H_2O(l)$

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

$Mg(OH)_2(aq)+2HNO_3(aq)\rightarrow Mg(NO_3)_2(aq)+H_2O(l)$

The ionic equation in separated aqueous solution will be,

$Mg^{2+}(aq)+2OH^-(aq)+2H^{+}(aq)+2NO_3^{-}(aq)\rightarrow H_2O(l)+Mg^{2+}(aq)+2NO_3^{-}(aq)$

In this equation, $Mg^{2+}\text{ and }NO_3^-$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$2H^{+}(aq)+2OH^-(aq)\rightarrow H_2O(l)$

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podryga [215]

Feso3 compound name

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Hope this helps!

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3 years ago

A student dilutes 50.0 mL of a 0.10 mol/L to 0.010 mol/L. Which statement is true?

VLD [36.1K]

The total amount of solute decreases.

6 0

3 years ago

The alkali earth metal beryllium (Be) engages in a chemical reaction and loses all of its valence electrons.

denpristay [2]

The loss of electron from an results in the formation of cation represented by the positive charge on the element whereas gaining of electron results in the formation of anion represented by the negative charge on the element.

The alkali earth metal beryllium ( $Be$ ) belongs to the second group of the periodic table. The ground state electronic configuration of $Be$ is: $1s^{2}2s^{2}$

From the electronic configuration it is clear that it has 2 valence electrons in its valence shell ( $2s^{2}$ ).

After losing all valence electrons that is 2 electrons from $2s$ orbital. The electronic configuration will be:

$1s^{2}2s^{0}$

Since, lose of electron is represented by positive charge on the element symbol. So, the beryllium will have +2 charge on its symbol as $Be^{2+}$ .

Hence, beryllium will have 2+ charge on it after losing all its valence electrons in the chemical reaction.

6 0

3 years ago

Read 2 more answers

An atom of titanium has 22 protons and 26 neutrons. If the atoms loses one electron, what will be the charge on the ion that for

Alja [10]

It’s +21 (c) if i answered late my apologies

5 0

3 years ago

Four springs are stretched to the same distance from the equilibrium position. The spring constants are listed in the table. A 2

svp [43]

Answer:

The correct option is;

X, W, Y, Z

Explanation:

The parameters given are;

Spring (S), Spring Constant (N/m)

W, 24

X, 35

Y, 22

Z, 15

The equation for elastic potential energy, $E_e$ , is $E_e = 0.5 \times k \times x^2$

The above equation can also be written as $E_e =\dfrac{1}{2} \times k \times x^2$

Where:

k = The spring constant in (N/m)

x = The spring extension

Therefore, since the elastic potential energy, $E_e$ , of the spring is directly proportional to the spring constant, k, we have the springs with higher spring constant will have higher elastic potential energy, $E_e$ , therefore the correct order is as follows;

X > W > Y > Z

9 0

3 years ago