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Lapatulllka [165]
2 years ago
12

why do clothes dry up faster in summer than in winter. ( Hint : The heat of the sun is more in summer ).why do clothes dye a pas

tor in summer than in winter 10th the heat of the sun is more in summer ​
Chemistry
1 answer:
ratelena [41]2 years ago
3 0

The temperature in the sunny area is higher than in the shade and evaporation takes place at a faster rate at high temperature. Hence, clothes dry quickly in summer.

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20 POINTS!!! PLS HELP ME
Gala2k [10]

Answer:

they just add heat, then it turns to water vapor

Explanation:

The first h20 is water the arrow represents adding heat, and the second h20 represent water vapor (water as a gas)

5 0
3 years ago
Read 2 more answers
Drag each label to the correct location on the image identify the parts of the energy diagram
diamong [38]
If you would’ve attached a picture I’m sure it would’ve been a lot easier.
4 0
2 years ago
Read 2 more answers
NH4NO3, whose heat of solution is 25.7 kJ/mol, is one substance that can be used in cold pack. If the goal is to decrease the te
makvit [3.9K]

Answer:

There are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

Explanation:

To decrease the temperature of the solution there are necessaries:

4,184J/g°C×(5,0°C-25,0°C)×(100,0g+X) = -Y

8368J + 83,68J/gX = Y <em>(1)</em>

Where x are grams of NH₄NO₃ you need to add and Y is the energy that you need to decrease the heat.

Also, the energy Y will be:

Y = 25700J/mol×\frac{1mol}{80,043g}X

Y = 321J/g X <em>(2)</em>

Replacing (2) in (1)

8368J + 83,68J/g X = 321J/g X

8363J = 237,32J/gX

<em>X = 35,2g</em>

<em />

Thus, there are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

I hope it helps!

6 0
3 years ago
The rate of effusion of oxygen to an unknown gas is 0.935. what is the other gas?
Kamila [148]

Answer:

N2

Explanation:

Rate of effusion is defined by Graham's Law:  

(Rate 1/Rate 2) = (sqrt (M2)/ sqrt (M1))

(Where M is the molar mass of each substance. )

Molar Mass of oxygen, O2, is 32 (M1).

Rate of effusion of O2 to an unknown gas is .935(Rate 1).  

Rate 2 is unknown so put 1.

Solve for x (M2).

.935/1 = sqrt x/ sqrt32

.935 x sqrt 32 = sqrt x

5.29 = sq rt x

5.29^2 = 27.975 = 28  

N2 has a molar mass of 28 so it is the correct gas.

4 0
3 years ago
8. If the temperature of a piece of steel decreases, what happens to its density?
Verdich [7]

Answer:

I think the answer is the 3rd one

3 0
2 years ago
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