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Marina CMI [18]
3 years ago
15

Name a substance which will undergo changes from solid to liquid to gas between 0c and 100c ​

Chemistry
1 answer:
Viefleur [7K]3 years ago
3 0

Answer:

WATER

Explanation:

Water melting  point 0 c boiling 100c

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2C_H. + 702 — 400, + 6H2O
astra-53 [7]

Balanced Eqn

2

C

2

H

6

+

7

O

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4

C

O

2

+

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H

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By the Balanced eqn

60g ethane requires 7x32= 224g oxygen

here ethane is in excess.oxygen will be fully consumed

hence

300g oxygen will consume  

60

⋅

300

224

=

80.36

g

ethane

leaving (270-80.36)= 189.64 g ethane.

By the Balanced eqn

60g ethane produces 4x44 g CO2

hence amount of CO2 produced =

4

⋅

44

⋅

80.36

60

=

235.72

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and its no. of moles will be  

235.72

44

=5.36 where 44 is the molar mass of Carbon dioxide

hope this helps

6 0
3 years ago
The maximum number of trees that can be grown in an area and have all of the resources they need to survive is the forest's ____
alisha [4.7K]

Answer:

growth limit for trees

Explanation:

the awnser is the growth limit for trees

6 0
2 years ago
Read 2 more answers
if the Celsius temperature of a gas at constant pressure is increased from 10 Celsius to 20 Celsius the volume is
svet-max [94.6K]

Answer:

               The volume is increased.

Explanation:

                     According to <em>Charles' Law</em>, " <em>at constant pressure the volume and temperature of the gas are directly proportional to each other</em>". Mathematically this law is presented as;

                                                    V₁ / T₁ = V₂ / T₂   -----(1)

In statement the data given is,

T₁  =  10 °C  =  283.15 K                    ∴  K  =  273.15 + °C

T₂  =  20 °C  =  293.15 K

So, it is clear that the temperature is being increased hence, we will find an increase in volume. Let us assume that the starting volume is 100 L, so,

V₁  =  100 L

V₂  =  Unknown

Now, we will arrange equation 1 for V₂ as,

                                                    V₂  =  V₁ × T₂ / T₁

Putting values,

                                     V₂  = 100 L × 293.15 K / 283.15 K

                                     V₂  = 103.52 L

Hence, it is proved that by increasing temperature from 10 °C to 20 °C resulted in the increase of Volume from 100 L to 103.52 L.

3 0
3 years ago
Anyone could help me out?
Hoochie [10]

1.4 mg/dL = 0.014 g/L

Explanation:

Milligrams per deciliter to grams per liter

There is 1000 grams of mg/dL of 1 g/L

8 0
3 years ago
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A screw decreases the amount of work done.<br><br> True<br> False
victus00 [196]

Answer:

tru

Explanation:

4 0
3 years ago
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