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Ket [755]
3 years ago
10

The part in the middle with a coil of wire wrapped around a metal shaft is part of an electric motor. What is it?

Chemistry
2 answers:
evablogger [386]3 years ago
4 0

Answer:

  rotor

Explanation:

The part of the motor being pointed to is called the <em>rotor</em>.

KiRa [710]3 years ago
3 0
<h2>Question:</h2>
  • The part in the middle with a coil of wire wrapped around a metal shaft is part of an electric motor. What is it?

<h3>Answer : </h3>
  • Rotor

<h3>More About Rotor:</h3>

⟹ The rotor is a moving component of an electromagnetic system in the electric motor, electric generator, or alternator. Its rotation is due to the interaction between the windings and magnetic fields which produces a torque around the rotor's axis.

⟹ The stator core, stator winding and the outer frame are the three parts of the stator whereas the rotor core and field winding are the parts of the rotor. The three-phase supply is given to the winding of the stator. The rotor is excited by the DC supply.

⟹ The rotor speed, rotational speed of the rotor, is usually measured in rotations per minute (rpm) or tip speed in feet per minute.

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3 years ago
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Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt% methanol and the second contain
RoseWind [281]

Answer:

M_{per}= 52.86

W_{per}=47.14

Explanation:

<u>First mixture</u>:

40 wt% methanol - 60 wt% water 200 kg

m_{met1}=200 kg * 0.4= 80 kg

m_{wat1}=200 kg * 0.6= 120 kg

<u>Second mixture</u>:

70 wt% methanol - 30 wt% water 150 kg

m_{met2}=150 kg * 0.7= 105 kg

m_{wat2}=150 kg * 0.3= 45 kg

Final mixture:

m_{metF=80 kg + 105 kg= 185 kg

m_{watF}=120 kg + 45 = 165 kg

M_{per}=\frac{185 kg}{185 kg + 165 kg}*100= 52.86

W_{per}=\frac{165 kg}{185 kg + 165 kg}*100=47.14

If, the compositions are constant, the only variables are the mass of each mixture used in the final one, so there can be only one independent balance.

8 0
3 years ago
Given pH = 3.50 Find: [H3O+] and [OH-] Is this acidic, basic or neutral?
lys-0071 [83]

Answer:

Explanation:

Given parameters:

           pH = 3.50

Unknown:

    concentration of [H₃0⁺] = ?

    concentration of [OH⁻] = ?

Solution:

In order to find the unknown, we use some simple expressions which best explains the pH scale and the equilibrium systems of aqueous solutions.

         pH = -log₁₀[H₃O⁺]

         [H₃O⁺] = inverse log₁₀ (-pH) = 10^{-pH} = 10^{-3.5}

          [H₃O⁺] = 3.2 x 10⁻⁴moldm⁻³

       

For the  [OH⁻]:

       we use : pOH = -log₁₀ [OH⁻]

     Recall: pOH + pH = 14

                  pOH = 14 - pH = 14 - 3.5 = 10.5

  Now we plug the value of pOH into pOH = -log₁₀ [OH⁻]

                                   [OH⁻] = 10^{-pOH}

                        [OH⁻] = 10^{-10.5} = 3.2 x 10⁻¹¹moldm⁻³

The solution is acidic as the concentration of H₃0⁺ is more than that of the OH⁻ ions.

                   

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