Question

V^2+16v+ ? Make the expression a perfect square

Answer 1

$(a\pm b)^2=a^2\pm 2ab+b^2\\\\v^2+16v+?=v^2+2v\cdot8+?\\\\therefore\ ?=8^2\\\\\\Answer:\boxed{v^2+16v+64=(v+8)^2}$

Answer 2

V² + 16v + 64
v² + 8v + 8v + 64
v(v) + v(8) + 8(v) + 8(8)
v(v + 8) + 8(v + 8)
(v + 8)(v + 8)
(v + 8)²