Using the z-distribution, it is found that the 95% confidence interval for the difference is (-1.3, -0.7).
<h3>What are the mean and the standard error for each sample?</h3>
Considering the data given:


<h3>What is the mean and the standard error for the distribution of differences?</h3>
The mean is the subtraction of the means, hence:

The standard error is the square root of the sum of the variances of each sample, hence:

<h3>What is the confidence interval?</h3>
It is given by:

We have a 95% confidence interval, hence the critical value is of z = 1.96.
Then, the bounds of the interval are given as follows:
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:
127.17 cm²
Step-by-step explanation:
- Area of a semicircle: 1/2*π*r²
- π (pi) = 3.14
- r (radius) = d (diamater) / 2 => 18/2 = 9 cm
A = 1/2*π*r²
A = 1/2*3.14*9²
A = 1/2*3.14*81
A = 3.14*40.5
A = 127.17 cm²
Therefore, the area of the semicircle is 127.17 cm²
Hope this helps!
Answer:
211
Step-by-step explanation:
Answer:
30 pushups
Step-by-step explanation:
25/100 = x/120
so, 120x25 = 100x
3000 = 100x
3000/100= x
x = 30
so, Lauren has completed 30 push-ups.