Answer:
ASA and AAS
Step-by-step explanation:
We do not know if these are right triangles; therefore we cannot use HL to prove congruence.
We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.
We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.
Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.
Answer:
140 cm^2
Step-by-step explanation:
Formula for area of a Parallelogram: base*height
14 cm * 10cm = 
X = 19.
Explanation:
This expression is vertical from the angle 135, meaning it is congruent. With that being said, we would need to find what 7 multiplies by to give us 2 less than 135, which would be 133. Because 133 divided by 7 equals 19, x = 19. If we plug this in, we get the following equation: 7(19) + 2 = 135.
Corresponding angles are in the same relative position of an intersection.
The matching corner to VQR would be ZRT
