If a2 -2ab + b2 = 9 and a![\begin{gathered} a^2-2ab+b^2=9 \\ aStep 1 factorize[tex]\begin{gathered} a^2-2ab+b^2=(a-b)^2 \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D9%20%5C%5C%20a%3C%2Fp%3E%3Cp%3E%EF%BB%BFStep%201%20%3C%2Fp%3E%3Cp%3Efactorize%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D%28a-b%29%5E2%20%5C%5C%20%20%5Cend%7Bgathered%7D)
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3
Answer:
3/2
Step-by-step explanation:
-4-5/4-(-2)
-9/6
3/2
36 + 18 = 54
(1) 18/54 = 1/3 = 33%
43 + 24 = 67
(2) 24/67 = 36%
I hope these are right
It will become 61
because anything above 0.5 rounds up
Answer:
y = -5x/4 - 8
Step-by-step explanation:
Two lines that are perpendicular have slopes that are opposite reciprocals.
Since the slope of the given line is 4/5, the opposite reciprocal of that is -5/4. So the equation has a slope of -5/4.
Since we know the coordinate of a point of the other equation, we can plug that into the point-slope form equation y - y1 = m(x - x1):
y - 2 = -5/4(x-(-8))
Simplify:
y - 2 = -5/4(x+8)
y - 2 = -5x/4 - 10
So the equation in slope-intercept form is:
y = -5x/4 - 8
