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3 years ago

-12×4÷6-4= how much is it

Mathematics

2 answers:

Nat2105 [25]3 years ago

8 0

Answer:

-12

Step-by-step explanation:

Hope this helps :D

Vera_Pavlovna [14]3 years ago

4 0

-24

hope that helps

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Mean median mode range of 13,11,8,8,12,8

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2 years ago

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The height of the pyramid is 12 inches. This pyramid has a rectangular base with length of 10 inches and width of 9 inches. What

xenn [34]

Answer:

1080"

Step-by-step explanation:

12*10= 120

120*9= 1080

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3 years ago

-2 - 6

Tatiana [17]

Answer:

-8

-15

-8

-60

-9

-12

Step-by-step explanation:

-2 - 6 = -8

8 + (-4) = 4

10 + (-25) = -15

-15 - (-7) = -8

-6 - (-13) = 7

-7 x -6 = 42

-12 x 5 = -60

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72/-8 = -9

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3 years ago

4 - 0.25(10) +0.5(5)

nlexa [21]

Answer:

Step-by-step explanation:

5 0

2 years ago

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If sinθ = -1/2 and θ is in Quadrant III, then tanθ = _____.

Gnom [1K]

Answer: $\tan \theta=\dfrac{1}{\sqrt3}.$

Step-by-step explanation: Given that

$\sin\theta=-\dfrac{1}{2}$ and $\theta$ lies in Quadrant III.

We are to find the value of $\tan \theta.$

We will be using the following trigonometric identities:

$(i)~sin^2\theta+\cos^2\theta=1,\\\\(ii)~\dfrac{\sin\theta}{\cos{\theta}}=\tan \theta.$

We have

$\tan\theta\\\\\\=\dfrac{\sin\theta}{\cos\theta}\\\\\\=\dfrac{\sin\theta}{\pm\sqrt{1-\sin^2\theta}}\\\\\\=\pm\dfrac{-\frac{1}{2}}{\sqrt{1-\left(\frac{1}{2}\right)^2}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\sqrt{1-\frac{1}{4}}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\frac{\sqrt3}{2}}\\\\\\=\pm\dfrac{1}{\sqrt3}.$

Since $\theta$ lies in Quadrant III, so tangent will be positive.

Thus,

$\tan \theta=\dfrac{1}{\sqrt3}.$

8 0

3 years ago

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-12×4÷6-4= how much is it​

-12×4÷6-4= how much is it