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sweet [91]
3 years ago
8

What function is the square root parent function, F(x) =

e="\sqrt{x}" alt="\sqrt{x}" align="absmiddle" class="latex-formula"> the inverse of?
A. F(x) = x^2, where x ≥ 0
B. F(x) = |x|
C. F(x)=\frac{1}{\sqrt{x} }
D. F(x) = x^2
Mathematics
2 answers:
murzikaleks [220]3 years ago
8 0

You can think of an <em>inverse </em>function as a function that “unwraps” x from whatever operations are attached to it. In the case of F(x) = √x, we can ”unwrap” x by squaring it. This narrows our options down to either A or D. Keep in mind that since there are no real number solutions to the square root of a negative number, we need to limit our domain to non-negative values. In other words, x ≥ 0. With that restriction, our answer is A.

nikitadnepr [17]3 years ago
5 0
<h2>Hello!</h2>

The answer is:

The inverse of the given function is:

A. f(x)^{-1}=x^{2}

Where,

x\geq 0

<h2>Why?</h2>

Inversing a function involves inversing the function variables. If we want to inverse a function, we need to rewrite the variable "x" with "y" and rewrite the variable "y" with "x", and then, isolate the variable "y".

Also, the domain of the original function will be the range of its inverse function, and the range of the original function, will be the domain of the its inverse function.

We are given the function:

f(x)=\sqrt{x}

f(x)=y=\sqrt{x}

So, inversing we have:

y=\sqrt{x}

x=\sqrt{y}

(x)^{2}=(\sqrt{y})^{2}\\\\x^{2}=(y^{\frac{1}{2}})^{2}\\\\x^{2}=y^{\frac{2}{2} }\\\\x^{2}=y

So, we have that the given function is only "part" of its inverse function, since negative square roots does not exist, it means that the domain of the given function starts from the number 0 taking only positive numbers.

Hence, we have that the answer is:

A. F(x)=x^{2}

Where,

x\geq 0

Have a nice day!

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There are 8 ways.

Step-by-step explanation:

For each employee there are two possibilities: first office and second office.

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2^{3} = 8

We can also look at this problem like suppose ABC are employees.

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The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont
BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

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\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)

and its cumulative distribution function (CDF) is

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• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

\bf P(A | B) = P(B)P(B) = (P(B))^2

We have  

\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237

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\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}

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This means that,

<em>Probability that at least one of them needs replacement at the first inspection =  </em>

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Firlakuza [10]

Answer:

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a = π * r²

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Answer:

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3 years ago
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