Rule: Add 3, subtract 2. first term 7

2 answers:

6 0

By adding 3 then subtracting 2, you're pretty much just adding 1.

Starting from 7;

7, 8, 9, 10, 11, 12, etc.

I hope that helps!

Ulleksa [173]3 years ago

5 0

It is easier to just simplify that, so yu would get 1 (if 3-2)
And, just add 1 to the next number: 8, 9, 10, 11...

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3 years ago

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posledela

$C= \left[\begin{array}{cc}1&-2\\-3&7\end{array}\right] \\ C^{-1}= \left[\begin{array}{cc}7&2\\3&1\end{array}\right] \\ \left[\begin{array}{cc}7&2\\3&1\end{array}\right] \times \left[\begin{array}{ccccc}7&-28&-25&-35&-2\\-21&107&90&123&17\end{array}\right] \\ =\left[\begin{array}{ccccc}49-42&-196+214&-175+180&-245+246&-14+34\\21-21&-84+107&-75+90&-105+123&-6+17\end{array}\right] \\ =\left[\begin{array}{ccccc}7&18&5&1&20\\0&23&15&18&11\end{array}\right]$
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3 years ago

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S_A_V [24]

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Decide whether quadrilateral ABCD with vertices 4(3,1), B(-1,-1) C(1,3), and D(5.5) is a rectangle, rhombus,square, or parallelo

Sergeeva-Olga [200]

Answer: rhombus

Step-by-step explanation:

By inspection, we can tell that there are no right angles, so we can determine it is not a square or a rectangle.

From the options, it is implied that it is a parallelogram, so to determine if it is a rhombus, we can determine if there is a pair of consecutive congruent sides.

By the distance formula,

$AB=\sqrt{(-1-3)^{2}+(-1-1)^{2}}=\sqrt{16+4}=2\sqrt{5}\\BC=\sqrt{(-1-1)^{2}+(-1-3)^{2}}=\sqrt{4+16}=2\sqrt{5}$

As AB=BC, there is indeed a pair of consecutive congruent sides, and thus the most specific classification is a rhombus

5 0

2 years ago