Answer:
3
Step-by-step explanation:
A direct variation is of the form
y = kx
We know x and y so we can find k
81 = k *27
Divide each side by 27
81/27 = 27k/27
3=k
The constant of variation is 3
Answer:
a) 3 b) 5 c) 7 d) 9
Step-by-step explanation:
For this, you want to replace x in the equation y=x+5 with each of the values listed.
For the first one, -2, the equation becomes y=-2+5, which is solved to y=3.
For the second one, 0, the equation becomes y=0+5, which is solved to y=5.
For the third one, 2, the equation becomes y=2+5, which is solved to y=7.
For the last one, 4, the equation becomes y=4+5, which is solved to y=9.
**This content involves solving algebraic equations with a known variable, which you may wish to revise. I'm always happy to help!
Answer:
(-2, 1)
Step-by-step explanation:
Systems of equations can be solved using different methods. For this set of systems, you can multiply each equation by a factor in order to eliminate a variable and solve for the other variable:
-3(-5x - 3y = 7) or 15x + 9y = -21
5(-3x - 4y = 2) or <u>-15x -20y = 10</u>
-11y = -11
y = 1
Solve for x: -5x - 3 = 7
Add 3 to both sides: -5x -3 + 3 = 7 + 3 or -5x = 10
Solve for x: x = -2
(-2, 1)
The answer is b. 11.
You can find this by multiplying the two parenthesis together. In order to do this, you can use a multiplying process known as FOIL (First, Outer, Inner, Last), where you multiply parts of the parenthesis in this order to make sure you do so properly.
First Numbers:
2x * x = 2x^2
Outer Numbers:
2x * 6 = 12x
Inner Numbers:
-1 * x = -1x
Last Numbers:
-1*6 = -6
Now place them all in that order and simplify.
2x^2 + 12x - x - 6 ---> simplify x terms
2x^2 + 11x - 6
Since the middle term (the one with the x value) has a coefficient of 11, that gives us a b value of 11.
Answer:
A repeating decimal or recurring decimal is decimal representation of a number whose digits are periodic (repeating its values at regular intervals) and the infinitely repeated portion is not zero. The infinitely repeated digit sequence is called the repetend or reptend.
