Answer:
x = 6
Step-by-step explanation:
<em>If </em><em>two secants</em><em> are drawn from</em><em> a point outside </em><em>the circle, then the </em><em>product</em><em> of the lengths of</em><em> one secant </em><em>and its</em><em> external segment</em><em> equals the </em><em>product </em><em>of the lengths of</em><em> the other secant </em><em>and its</em><em> external segment</em><em> </em>
Let us solve the question.
∵ There is a circle in the given figure
∵ There are two secants intersected at a point outside the circle
∵ The length of one of them = 8
∵ The length of its external segment = x
∵ The length of the other secant = 4 + 8 = 12
∵ The length of its external segment = 4
→ By using the rule above
∴ 8 × x = 12 × 4
∴ 8x = 48
→ Divide both sides by 8
∴ x = 6
Answer:
x=45.5
Step-by-step explanation:
sum of angles of a quadrilateral is 360°
so 3x - 11+x+8+x-8+2x+7+x=360°
or 8x-4=360
or, x=364÷8
hence
x=45.5
Step-by-step explanation:
<u>Step 1: Find the correct option</u>
If you look at the attached photo, the option that fits those points is option B, therefore, the correct answer is B
Answer: Option B
<em>Look at the attachment:</em>
Answer:
<u>(7.5-2.1) /2</u>
<u>If the shortest side measures 2.1 m</u>.
<em>7.5-2.1 =5.4.</em> Then divide by 2 each side is 2.7m
Answer:
f(10) = 8
Step-by-step explanation:
f(x) = 4(x - 8)
Let x = 10
f(10) = 4 ( 10-8)
= 4 ( 2)
= 8
