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Snowcat [4.5K]
3 years ago
13

If KM = NO and NO = PQ, then KM = PQ.

Mathematics
2 answers:
uysha [10]3 years ago
4 0
The answer is D. <span>transitive property (algebra lesson)
</span>
Nana76 [90]3 years ago
3 0

Answer:

C.

transitive property

Step-by-step explanation:


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Plz help ASAP number 4 I️ have B and 7 I️ have c plz help with the rest
Veronika [31]

Answer:

5 is interpolation

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4 0
3 years ago
How do I find the area of the shaded region? Thanks!!
bazaltina [42]

Answer:

The radius of a circumcircle of an equilateral triangle is equal to (a / √3), where ‘a’ is the length of the side of equilateral triangle.

Circle Radius = 16 / sq root (3)

Circle Radius = 9.237604307

Circle Area = PI * radius ^ 2

Circle Area = PI * 85.3333333333

Circle Area = 268.083

Equilateral Triangle area = side^2 * sq root (3) / 4

Equilateral Triangle area = 16^2 * 0.4330127019

Equilateral Triangle area = 110.85

Shaded region = 268.083 - 110.85

Shaded region = 157.233

Step-by-step explanation:

7 0
2 years ago
How many gallons of paint are required to paint the walls of a building having l= 50 ft w= 40 ft. h =80ft.
Brums [2.3K]
50*40*80=160000 to find the total square feet

then you divide 160000/500 to figure out the total amount of gallons of paint you need

you need 320 gallons of paint
5 0
3 years ago
A parking facility has five parking levels and a parking lot. If each level has 75
Pachacha [2.7K]
Multiply 75*5 to get 375

then add 120 from the lot to get 495
4 0
2 years ago
Read 2 more answers
A force of F pounds is required to pull an object weighing W pounds up a ramp inclined at θ degrees from the horizontal. Find θ
Pie

Answer:

The value of θ is 20.105°

Step-by-step explanation:

Consider the provided information.

A force of F pounds is required to pull an object weighing W pounds up a ramp inclined at θ degrees from the horizontal.

Sine of angle is force over weight.

\sin\theta=\frac{F}{W}

Substitute F = 5500 pounds and W = 16,000 pounds in above formula.

\sin\theta=\frac{5500}{16000}

\sin\theta=\frac{11}{32}

\theta\approx20.105

Hence, the value of θ is 20.105°

5 0
2 years ago
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