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lesya692 [45]
3 years ago
8

Prove: m∠LYE=180°−m of arc EHL

Mathematics
1 answer:
noname [10]3 years ago
3 0
For information please
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Luis wants to buy a skateboard that usually sells for $79.99. All merchandise is discounted by 12%. What is the total cost of th
DIA [1.3K]

Answer:  $75.14

Step-by-step explanation:

to find out how much luis is saving with the discount you do

79.99 * 0.12

and get around 9 ish dollars

after that you do sales tax and get $75.14 dollars hope this helped <3

3 0
3 years ago
A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

6 0
3 years ago
Please help me and If your answer is wrong or not appropreat I will report it
arsen [322]

Answer:

972 x^16 y^24

Step-by-step explanation:

Simplify the following:

(-2 x^3 y^7)^2 (3 x^2 y^2)^5

Multiply each exponent in -2 x^3 y^7 by 2:

(-2)^2 x^(2×3) y^(2×7) (3 x^2 y^2)^5

2×7 = 14:

(-2)^2 x^(2×3) y^14 (3 x^2 y^2)^5

2×3 = 6:

(-2)^2 x^6 y^14 (3 x^2 y^2)^5

(-2)^2 = 4:

4 x^6 y^14 (3 x^2 y^2)^5

Multiply each exponent in 3 x^2 y^2 by 5:

4 x^6 y^14×3^5 x^(5×2) y^(5×2)

5×2 = 10:

4×3^5 x^6 y^14 x^(5×2) y^10

5×2 = 10:

4×3^5 x^6 y^14 x^10 y^10

3^5 = 3×3^4 = 3 (3^2)^2:

4×3 (3^2)^2 x^6 y^14 x^10 y^10

3^2 = 9:

4×3×9^2 x^6 y^14 x^10 y^10

9^2 = 81:

4×3×81 x^6 y^14 x^10 y^10

3×81 = 243:

4×243 x^6 y^14 x^10 y^10

4 x^6 y^14×243 x^10 y^10 = 4 x^(6 + 10) y^(14 + 10)×243:

4×243 x^(6 + 10) y^(14 + 10)

14 + 10 = 24:

4×243 x^(6 + 10) y^24

6 + 10 = 16:

4×243 x^16 y^24

4×243 = 972:

Answer: 972 x^16 y^24

8 0
2 years ago
Read 2 more answers
The sum of two
sergeinik [125]

Answer:

63

Step-by-step explanation:

let the two numbers be x,y (x>y)

Then x+y = 16 and x-y = 2

We know that (x+y)^2 - (x-y)^2 = 4xy

So 4xy = 16^2 - 2^2 => 4xy = (16+2)(16–2)

So xy = 18×14/4 = 63

Product of the numbers = 63

8 0
3 years ago
Please help SO CONFUSED
gulaghasi [49]

Answer:

SOH-CAH-TOA

h = \sqrt{ 9^{2} +5^{2} }

~~~~~~~~~~

H= \sqrt{106}

O= 5

A= 9

~~~~~~~~~~~~~~~~

Sin = \frac{5}{\sqrt{106 }  }

Cos= \frac{9}{\sqrt{106 }  }

Tan = \frac{5}{9  }

Step-by-step explanation:

5 0
2 years ago
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