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erma4kov [3.2K]
3 years ago
10

Which angle is an acute angle?

Mathematics
2 answers:
larisa [96]3 years ago
4 0

there is no acute angle.......

kirill [66]3 years ago
3 0

Answer:

angle CPB is an acute angle cause it's measure is less than 90°

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Harlamova29_29 [7]
36 divided by 3/4 is 48
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3 years ago
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Graph a system of equations to solve log (−5.6x + 1.3) = −1 − x. Round to the nearest tenth.
const2013 [10]

From the least to the greatest, the solutions are x ≈ -2.1 and x ≈ 0.2

the answers are -2.1 and 0.2.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have two systems of the equation:

y = log (−5.6x + 1.3)

y  = −1 − x

After plotting the above equation on the graph we will see two intersections point:

(-2.12, 1.12) and (0.221, -1.221)

So the least value is x = -2.12 ≈ -2.1

The greatest value is x = 0.221 ≈ 0.2

Thus, from the least to the greatest, the solutions are x ≈ -2.1 and x ≈ 0.2

the answers are -2.1 and 0.2.

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8 0
2 years ago
What is the image of the point (-3,-6) on rotation of 90 degrees about the origin ?
SOVA2 [1]

Answer:

(- 6, 3 )

Step-by-step explanation:

Under a rotation about the origin of 90°

a point (x, y ) → (y, - x ), thus

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6 0
3 years ago
Solve for &lt; x &lt; 180degrees
Tamiku [17]

Option C: 90° is the value of x.

Explanation:

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We need to solve the expression.

Thus, we have,

4+2 \sin x=14-8 \sin x

Subtracting both sides by 4, we have,

2 \sin x=10-8 \sin x

Adding both sides by 8 sin x, we get,

10 \sin x=10

Dividing both sides by 10, we have,

sin \ x=1

Taking sin^{-1} on both sides of the equation, we get,

x=sin^{-1}(1)

x=90^{\circ}

Thus, the value of x is 90°

Hence, Option C is the correct answer.

4 0
3 years ago
The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation
rodikova [14]

Answer: C) y=sin^-1 x

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point (1,\frac{\pi}{2}),

If this point satisfies the function,

For the function y=cos^{-1} x

If x = 1

y=cos^{-1}1=0

Thus,  (1,\frac{\pi}{2}) is not satisfying function  y=cos^{-1} x,

⇒ The graph of   y=cos^{-1} x is not passing through the point  (1,\frac{\pi}{2})

For the function y=cot^{-1}x

If x = 1

y=cot^{-1}1=\frac{\pi}{4}

Thus,  (1,\frac{\pi}{2}) is not satisfying function y=cot^{-1}x,

⇒ The graph of   y=cot^{-1}x is not passing through the point  (1,\frac{\pi}{2})

For the function y=sin^{-1} x

If x = 1

y=sin^{-1}1=\frac{\pi}{2}

Thus,  (1,\frac{\pi}{2}) is satisfying function y=sin^{-1} x,

⇒ The graph of   y=sin^{-1} x is passing through the point  (1,\frac{\pi}{2}).

For the function y=tan^{-1}x

If x = 1

y=tan^{-1}1=\frac{\pi}{4}

Thus,  (1,\frac{\pi}{2}) is not satisfying function  y=cos^{-1} x,

⇒ The graph of   y=tan^{-1} x is not passing through the point (1,\frac{\pi}{2}).

Hence, Option C is correct.

3 0
3 years ago
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