In a block in a blockchain, a resource which represent the transactional data, sender, receiver, and number of coins is: A. data.
<h3>What is a blockchain?</h3>
A blockchain can be defined as a digital and dynamic financial system that is designed and developed to be used in recording and maintaining transactions that are associated with or made through the use of a bitcoin, usually as a database containing various set of data.
In this context, we can infer and logically deduce that data is a resource that typically represent all of the transactional data, sender, recipient (receiver), and the number of bitcoins in a block in a blockchain.
Read more on blockchain here: brainly.com/question/25700270
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Answer:
see explaination
Explanation:
#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
double temp1,temp2,inc,cel;
int i=1;
while(i==1)
{
i=0;
cin>>temp1>>temp2>>inc;
if(temp2<temp1||inc<=0)
{
i=1;
cout<<"Starting temperature must be <= ending temperature and increment must be >0.0\n";
}
}
cout<<endl;
cout<<setw(15)<<"Fahrenheit"<<setw(15)<<"Celsius";
while(temp1<=temp2)
{
cel=(temp1-32)/1.8;
cout<<endl;
cout<<fixed<<setprecision(3)<<setw(15)<<temp1<<setw(15)<<cel;
temp1+=inc;
}
}
Please kindly check attachment for output.
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Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits