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SIZIF [17.4K]
2 years ago
13

Paul wants to gift wrap the boxes. He has 1,000.00 square inches of wrapping paper. Does Paul have enough to wrap all three boxe

s?
Mathematics
1 answer:
zhannawk [14.2K]2 years ago
5 0

Answer:

y

Step-by-step explanation:

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Find the slope (0, -3) and (9, 0) PLEASE SHOW YOUR WORK, WILL MARK BRAINLEIST
Flura [38]
<h3>Answer: slope = 1/3</h3>

===================================================

Work Shown:

Use the slope formula to get

m = (y2 - y1)/(x2 - x1)

m = (0 - (-3))/(9 - 0)

m = (0 + 3)/(9 - 0)

m = 3/9

m = 1/3

----------------

Basically we subtract the y coordinates, and do the same for the x coordinates as well (subtract in the same order). Afterward, divide the two results. Reduce the fraction as much as possible.

A slope of 1/3 means we move up 1 unit each time we move to the right 3 units.

The slope being positive means the line goes uphill as you read from left to right.

6 0
3 years ago
There are 3 star fighters and 10 aliens in the play space trek. Each alien costume takes 2 1/4 yards of material. How much mater
Leno4ka [110]

Answer:

  22.5 yards

Step-by-step explanation:

10 costumes at 2.25 yards each is ...

  10 · 2.25 = 22.5 . . . . yards of material

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3 years ago
Find the value of n. 4 × 62 = (4 x n) + (4 × 2)
tino4ka555 [31]
The answer is 1000 because 62x4= 248 and then you take 248 and multiply it by 4 and you get 992 then you have to multiply 4x2 which is 8 and then when you add 992+8, you would get 100 ;)
7 0
3 years ago
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Answer:6 minutes

Step-by-step explanation:

6 0
3 years ago
Prove that the sum of the squares of any two odd numbers is always even
ValentinkaMS [17]

Answer:

proof below

Step-by-step explanation:

Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)

Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;

(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2

= 2(2a^2 + 2a + 2b^2 + 2b + 1)

Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.

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3 years ago
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