The percent by mass : 6.3%
<h3>Further explanation</h3>
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
mass of potassium nitrate = 8.4 g⇒solute
- mass of solution = mass of solute+mass of solvent(water)
mass of potassium nitrate + mass of water = 8.4 g + 125 g =133.4 g
Percent by mass of the solute :
![\tt =\dfrac{mass~solute}{mass~solution}\times 100\%\\\\=\dfrac{8.4}{133.4}\times 100\%\\\\=6.3\%](https://tex.z-dn.net/?f=%5Ctt%20%3D%5Cdfrac%7Bmass~solute%7D%7Bmass~solution%7D%5Ctimes%20100%5C%25%5C%5C%5C%5C%3D%5Cdfrac%7B8.4%7D%7B133.4%7D%5Ctimes%20100%5C%25%5C%5C%5C%5C%3D6.3%5C%25)
Answer:
Name Strontium
Atomic Mass 87.62 atomic mass units
Number of Protons 38
Number of Neutrons 50
Number of Electrons 38
Answer:
1.62 × 10⁻³ M s⁻¹
Explanation:
Let's consider the following reaction.
2 NO₂ + F₂ = 2 NO₂F
The generic rate law is:
rate = k × [NO₂]ᵃ × [F₂]ᵇ
where,
- a and b: reaction orders with respect to the reactants
The reaction is first order in NO₂ and first order in F₂ and the rate constant is k = 1.58 × 10⁻⁴ M⁻¹ s⁻¹.
The rate law is:
rate = 1.58 × 10⁻⁴ M⁻¹ s⁻¹ × [NO₂] × [F₂]
When [NO₂] = 2.84 M and [F₂] = 3.60 M, the reaction rate is:
rate = 1.58 × 10⁻⁴ M⁻¹ s⁻¹ × 2.84 M × 3.60 M
rate = 1.62 × 10⁻³ M s⁻¹
<h3>The mass of the gas, on the other hand, does depend on volume. Cutting the volume in two cuts the mass in two. The mass in each section of the tank is one half the mass of the entire tank.</h3>