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Elis [28]
2 years ago
13

Someone pls help me I will make you brain

Chemistry
1 answer:
Dahasolnce [82]2 years ago
4 0
Hey what’s the question?
I can’t see anything
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How is helium different from other noble gases?
Slav-nsk [51]
Helium only possesses two valence electrons, while the other noble gasses posses eight
3 0
2 years ago
12 POINTS!! Which step would help a student find the molecular formula of a compound from the empirical formula?
Novosadov [1.4K]
Your answer would be D.
5 0
3 years ago
It requires 334 kJ of heat to melt 1 kg of ice. The largest known iceberg had a volume of about 3.1 x 1013 m³. How much heat was
umka21 [38]

The  amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.

<h3>What is the amount of heat required to melt an iceberg that has a volume of about 3.1 x 1013 m³?</h3>

The heat required to melt a unit mass of ice is known as the latent heat of fusion.

The latent heat of fusion of ice of 1 kg= 334 kJ of heat

Mass of iceberg = 3.1 x 10¹³ m³ * 917 kg = 2.8427 * 10¹⁶ kg

Amount of heat required = 2.8427 * 10¹⁶ * 334 = 9.58 * 10¹⁸ kJ.

Therefore, the amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.

Learn more about latent heat of fusion at: brainly.com/question/87248

#SPJ1

8 0
2 years ago
The half life of carbon is 5,730 years. What fraction of the original 14/6 C would be in a wooden axe handle that was 17,190 yea
Mariana [72]

Answer:

\frac{1}{8}  

Explanation:

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

\text{17 190 y} \times \frac {\text {1 half-life}}{\text{5730 y}} = \text{3 half-lives}  

We can construct a table.

<u>No of half-lives</u>  <u>Fraction remaining</u>

            1                       \frac{1}{2}  

            2                      \frac{1}{4}  

            3                      \frac{1}{8}  

The general formula is

\text{Fraction remaining} = \frac{1}{2^{n}}

where <em>n</em> = the number of half-lives.

Thus, \frac{1}{8} of the original carbon remains after 17 190 y.

8 0
3 years ago
) Starting with 5.00 g barium chloride n hydrate yields 4.26 g of anhydrous barium chloride after heating. Determine the integer
RSB [31]

Answer:

2

Explanation:

Mass of water molecule = mass of hydrated salt - mass of anhydrous salt

Mass of water molecule = 5.00 - 4.26 = 0.74g of water molecule.

Number of moles = mass / molarmass

Molar mass of water = 18.015g/mol

No. of moles of water = 0.74 / 18.015 = 0.0411 moles.

Mass of BaCl2 present =?

1 mole of BaCl2 = 208.23 g

X mole of BaCl2 = 4.26 g

X = (4.26 * 1) / 208.23

X = 0.020

0.020 moles is present in 4.26g of BaCl2

Mole ratio between water and BaCl2 =

0.0411 / 0.020 = 2

Therefore 2 molecules of water is present the hydrated salt.

4 0
3 years ago
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