A parabola has a vertex of (3,-2) and a y intercept of 7. what is the equation of this parabola
1 answer:
Answer:
Step-by-step explanation:
y=ax^2+bx+c
when x=0,y=7 so c=7
when x=3 then y=a*3^2+b*3+7=-2
9a+3b+7=-2
9a+3b=-2-7
9a+3b=-9
V(3,-2)
3=-b/2a
-b=3*2a
b=-6a
9a+3*(-6a)=-9
9a-18a=-9
-9a=-9
a=1
b=-6*1
b=-6a
b=-6
so y=x^2-6x+7
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Hope this helps. :)