(t^2+1)^100
USE CHAIN RULE
Outside first (using power rule)
100*(t^2+1)^99 * derivative of the inside
100(t^2+1)^99 * d(t^2+1)
100(t^2+1)^99 * 2t
200t(t^2+1)^99
Answer: Yes
Step-by-step explanation:
Answer:
ITs blury
Step-by-step explanation:
Answer:
The expected value of lateness
hours.
Step-by-step explanation:
The probability distribution of lateness is as follows:
Lateness P (Lateness)
On Time 4/5
1 Hour Late 1/10
2 Hours Late 1/20
3 Hours Late 1/20
The formula of expected value of a random variable is:

Compute the expected value of lateness as follows:


Thus, the expected value of lateness
hours.
Answer:
1) distributive property.
Step-by-step explanation:
Becca used the distributive property, in that she distributed (multiplied) 4 to all terms within the parenthesis:
4(x + 2) = 4x + 8
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