Answer: ATP and NADPH are produced in the light dependent stage
Explanation:
In the light dependent stage of photosynthesis, photoactivation of chlorophyll results in the splitting of water molecules and the transfer of energy to ATP and reduced nicotinamide adenine dinucleotide phosphate (NADPH).
NADPH and ATP are used to carryout the light-independent stage and not just ATP alone as claimed in the publication.
The phrase that needs correction is "ATP is generated in the light reactions "
The littoral zone is also known as the intertidal zone is the place where the land and sea meet and is found between the low and high tide zones. This diverse marine ecosystem is witnessed along the coastlines globally. It comprises ample nutrients and oxygen and is considered home to numerous species.
The littoral zone is further differentiated into vertical zones, like the spray zone and low tide zone. Spray zone also known as the upper littoral, and is dry in the majority of the time, but sprayed with water at the time of high tides. It gets flooded at the time of extreme high tides and storms.
The low tide zone also is known as the lower littoral zone, is generally found under water and gets exposed when the tide becomes abnormally low. The species in this zone are not well used to extreme temperatures and long duration of dryness.
Some of the common organisms found in both spray and low tide zones are isopods and limpets.
The answer is A:4,5,3,1,2.
Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
The reason the socks stick together, is because electrons from one fabric rub off onto another fabric by friction.
