I believe it would be 100 because the 9 in 99 would be the rounding spot and if you look to the right of it its another 9 which is greater than five so that would round up to 100
<h3>
Answer: 2x^2 + 6x - 4</h3>
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Work Shown:
f(x) - g(x) = [ f(x) ] - [ g(x) ]
f(x) - g(x) = ( 3x^2+x-3) - ( x^2-5x+1 )
f(x) - g(x) = 3x^2+x-3 - x^2+5x-1
f(x) - g(x) = (3x^2-x^2) + (x+5x) + (-3-1)
f(x) - g(x) = 2x^2 + 6x - 4
<span>The difference between two integers is at most 16
x1 - big integer
x2- small integer
</span><span>the smaller integer is 12
so
x2 = 12
substitution
</span>
<span>
solve for x1
however, note the fact larger
thus meaning
x1 > x2 applies to this problem
</span>
16 = k/11
You’re going to need to get K by itself
So you need to multiply 11 on both sides
to remove the denominator of 11
16 x 11 = 176
k/11 x 11 = k
So now the answer would be
176 = k
Hope this helped :)
One third written as a fraction is 1/3. You can also write it as a decimal by simply dividing 1 by 3 which is 0.33.
If you multiply 0.33 with 536 you will see that you will end up with the same answer as above.
You may also find it useful to know that if you multiply 0.33 with 100 you get 33.33. Which means that our answer of 178.67 is 33.33 percent of 536.
Solution : 178.67
