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jasenka [17]
3 years ago
13

40,897 in expanded form

Mathematics
1 answer:
Vlada [557]3 years ago
4 0

Answer:

Fourty thousand, eight hundred ninety seven.

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From the top of a vertical cliff 50 m high, the angle of depression of an object that is level with the base of the cliff is 70°
Svetlanka [38]

Answer:

The distance of the object from the base of cliff is 18.24 meters

Step-by-step explanation:

Given as :

The height of the vertical cliff = h = 50 meters

The distance of the object from the base of cliff = x meters

Let The angle of depression of object that level with cliff base = Ф = 70°

<u>Now, from figure</u>

Tan angle = \dfrac{\textrm perpendicular}{\textrm base}

I.e TanФ = \dfrac{\textrm AB}{\textrm OA}

Or, TanФ = \dfrac{\textrm h}{\textrm x}

Or, Tan 70° = \dfrac{\textrm 50 meters}{\textrm x meters}

Or, 2.74 = \dfrac{\textrm 50}{\textrm x}

∴ x =  \dfrac{\textrm 50}{\textrm 2.74}

I,e x = 18.24 meters

So, The distance of the object from the base of cliff = x = 18.24 meters

Hence,The distance of the object from the base of cliff is 18.24 meters Answer

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Step-by-step explanation:

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T + (-5) = 14<br> can someone solve the equation please?
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Answer: 19

Add 5 to both sides

t - 5 = 14

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