Answer:
<u>x-intercept</u>
The point at which the curve <u>crosses the x-axis</u>, so when y = 0.
From inspection of the graph, the curve appears to cross the x-axis when x = -4, so the x-intercept is (-4, 0)
<u>y-intercept</u>
The point at which the curve <u>crosses the y-axis</u>, so when x = 0.
From inspection of the graph, the curve appears to cross the y-axis when y = -1, so the y-intercept is (0, -1)
<u>Asymptote</u>
A line which the curve gets <u>infinitely close</u> to, but <u>never touches</u>.
From inspection of the graph, the curve appears to get infinitely close to but never touches the vertical line at x = -5, so the vertical asymptote is x = -5
(Please note: we cannot be sure that there is a horizontal asymptote at y = -2 without knowing the equation of the graph, or seeing a larger portion of the graph).
Answer:
Step-by-step explanation:
THIS is the answer if the equation looks like this. 
Answer:
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pls mark brainliest
Step-by-step explanation:
The first step is to locate the coordinates of the vertices of the arrow. From the graph,
A = (2, 1)
B = (2, 3)
C = (1, 3)
D = (3, 5)
E = (5, 3)
F = (4, 3)
G = (4, 1)
If (a, b) is reflected on the line y = - x, the coordinates of the image is (- b, - a)
By applying this rule, the new coordinates after reflecting the arrow over the line y = - x are
A'(- 1, - 2)
B'(- 3, - 2)
C'(- 3, - 1)
D'(- 5, - 3)
E'(- 3, - 5)
F'(- 3, - 4)
G(- 1, - 4)
