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stiks02 [169]
3 years ago
8

A homeowner doing some remodeling requires the services of both a plumbing contractor and an electrical contractor. If there are

15 plumbing contractors, and 10 electrical contractors available in the area, in how many ways can the contractors be chosen? E. 15 F. 10 G. 25 H. 150
Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0

Answer:

H. 150

Step-by-step explanation:

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In how many ways can the contractors be chosen?

One pumbling(from a set of 15)

One electrical(from a set of 10)

So

P_{(15,1)}*P_{(10,1)} = \frac{15!}{(15-1)!}*\frac{10!}{(10-1)!} = 15*10 = 150

So the correct answer is:

H. 150

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