How can you prevent online shopping risks

Give me give me keyboard on this phone please provide nice I can't type where is the keyboard.Give me give me keyboard on this p

RSB [31]

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7 0

2 years ago

Read 2 more answers

Krystal recorded her times for all her cross-country meets this season. To sort her data showing the lowest times first, what wi

devlian [24]

Sort ascending would be the correct one, since you are going from the lowest value to the highest

3 0

3 years ago

Read 2 more answers

System Architecture: Describe the system architecture. Specifically, be sure to address the corporate organization and culture,

alekssr [168]

Answer:

Explanation:

In information technology, architecture plays a major role in the aspects of business modernization, IT transformation, software development, as well as other major initiatives within the enterprise. IT architecture is used to implement an efficient, flexible, and high quality technology solution for a business problem, and is classified into three different categories: enterprise architecture, solution architecture and system architecture. Each of these classifications varies in their implementation and design, depending on the contextual business scope, organization structure, and corporate culture.

Architecture Level

Architecture level represents the scope boundary and granularity of details the architectural activity should take, based on organization hierarchy and communication audience.

Enterprise Architecture (Company level) aligns technological strategies and execution plans with business visions and objectives by providing architectural oversight and guidance. Enterprise architecture also drives consolidation, reuse, and economy of scale by addressing company-wide goals in a holistic way across all IT projects.

Solution Architecture (Department level) models a solution vision that defines the IT systems, business processes and reusable services for a specific business unit, spanning across business and technology architectures.

System Architecture (Team level) defines the structure of an information system in terms of various subsystem components and their relationships with internal and external systems. System architecture focuses on application, data, and technology, and is called software architecture in some organizations.

Before making decision regarding system architecture the designer must consider the following points:

Corporate organization and culture: System architecture must study day-to-day functions of business and users in order to understand corporate organization and culture. This will help in focusing on operational feasibility which will help in deciding other checklist items.
Enterprise resource planning (ERP): Most of the organization use ERP software these days and it is important for the analyst to understand the compatibility of the ERP which is used to the proposed system.
Total cost of ownership (TCO): System analyst must try to get solutions of different questions which helps in finding initial cost and cost which may add up during the development, which is total cost of ownership. This is most important at this will determine total cost and budget of system.
Scalability: Determining system ability to expand or downsize according to business requirements.
Security: What security system and policy needs to be implemented.

7 0

3 years ago

in a particular factory, a team leader is an hourly paid production worker who leads a small team. in addition to hourly pay, te

malfutka [58]

Facilitate team development for successful project completion. Through coaching and mentoring, provide teammates with technical leadership.

Establishing best practices and habits will help the team maintain high standards for the quality of its software. Identify and promote the team's potential development and improvement areas.

#include<iostream>

using namespace std;

/*C++ Function to print leaders in an array */

void printLeaders(int arr[], int size)

{

for (int i = 0; i < size; i++)

{

int j;

for (j = i+1; j < size; j++)

{

if (arr[i] <=arr[j])

break;

}

if (j == size) // the loop didn't break

cout << arr[i] << " ";

}

/* Driver program to test above function */

int main()

{

int arr[] = {16, 17, 4, 3, 5, 2};

int n = sizeof(arr)/sizeof(arr[0]);

printLeaders(arr, n);

return 0;

}

Learn more about Development here-

brainly.com/question/28011228

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7 0

1 year ago

Create a macro named mReadInt that reads a 16- or 32-bit signed integer from standard input and returns the value in an argument

timofeeve [1]

Answer:

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

Explanation:

For an assembly code/language that has the conditions given in the question, the program that tests the macro, passing it operands of various sizes is given below;

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

7 0

3 years ago