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liberstina [14]
3 years ago
9

Whether they are parallel, perpendicular or neither

Mathematics
1 answer:
galina1969 [7]3 years ago
8 0
Line 1 and 2 are parallel 
line 1 and 3 are parallel
line 2 and 3 are parallel
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Brainliest? :(
Svetlanka [38]

Answer:

(f\cdot g)(x)=2x^2+10x+12

(f-g)(x)=-x-1

(f+g)(1)=10

Step-by-step explanation:

\tt f(x)=x+3

\tt g(x)=2x+4

(f\cdot g)(x)=f(x)\cdot g(x)=(x+3)(2x+4)=2x^2+4x+6x+12

=2x^2+10x+12

(f-g)(x)=f(x)-g(x)=x+3-(2x+4)=x+3-2x-4

=-x-1

(f+g)(1)=f(1)+g(1)=1+3+2(1)+4

=4+2+4=10

~

7 0
2 years ago
True of False: (log x)^2=2log x. Explain your answer and show your work
Lubov Fominskaja [6]
False.
Only log(x^2)=2log(x)
For example, let x=10
(log(10))^2=1^2=1
yet 2log(10)=2*1=2
8 0
3 years ago
Leo sold 31 pieces of pottery at the Market. He sold half as many vases as plates. He sold 16 bowls. How many of each kind did L
never [62]
31 vases 63 plates and 19 bowls
8 0
3 years ago
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4[( 8 + 4)10] + 24 devided by 2^3
Nikolay [14]
4[(8+4)10] + 24
so 8 + 4 is 12. Multiply that by 10 and that's 120.
120 + 24 is 144
144 × 4 is 576
for "devided by 2^3" do you mean divided by 2/3?
If so then its 576 ÷ 2/3 = 96
8 0
3 years ago
What is the equation of the line that passes through the points (-3,4) and (6,7)
inn [45]
Y=mx+b, m=(y2-y1)/(x2-x1)

m=(7-4)/(6--3)=3/9=1/3

y=x/3 +b, now use either point to solve for b, I'll use (6,7)

7=6/3 +b

7=2+b

b=5 so our line is:

y=x/3 +5 or more neatly...

y=(x+15)/3
6 0
3 years ago
Read 2 more answers
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